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ahrayia [7]
2 years ago
11

7 A triangular sail has a base length of 2.5 av-ea of the is 3.75 square meters How tan is the A , , , ,. , , ,, .. -.

Mathematics
1 answer:
zavuch27 [327]2 years ago
7 0
The anser is 6.25. Can you help me on mines?
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What is the value of a in a/5 + 3= 8
OLga [1]

Answer:

Step-by-step explanation:

what is the value of a in a/5 + 3= 8

a/5 + 3= 8

a/5 = 8 - 3

a/5 = 5

a = 5 * 5

a = 25

3 0
2 years ago
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100 POINTS: ANSWER PROPERLY WITH STEPS SHOWN FOR BRAINLIEST AND POINTS!!!!!!!!!!!! GST AND PST VALUES ARE BASED ON CANADA ONTARI
neonofarm [45]

Answer:

yes i agree with you!!!

Step-by-step explanation:

5 0
3 years ago
If (2x+10) and (3x+10) form a linear pair<br>find angles<br>.​
Alex_Xolod [135]
Linear pair angles are always supplementary.
So,
(2x+10) +(3x+10) = 180
5x+20 = 180
5x =180-20
5x=160
x= 160/5
x=32
Hence, the angles are 74 & 104
4 0
2 years ago
A gambler has a fair coin and a two-headed coin in his pocket. He selects one of the coins at random. (a) When he flips the coin
Aleks04 [339]

Answer:

a) probability of choosing heads= 1/2 (50%)

b)  probability of choosing the fair coin knowing that it showed heads is= 1/3 (33.33%)

Step-by-step explanation:

Since the unfair coin can have 2 heads or 2 tails , and assuming both are equally possible . then

probability of choosing the fair coin  (named A)= 1/2

probability of choosing an unfair coin with 2 heads (named B)= (1-1/2)*1/2= 1/4

probability of choosing an unfair coin with 2 tails (named C)= (1-1/2)*(1-1/2)= 1/4

then

probability of choosing heads= probability of choosing A * probability of getting heads from A + probability of choosing B * probability of getting heads from B + probability of choosing C * probability of getting heads from C =

1/2*1/2 + 1/4*1 + 1/4*0 = 2/4 = 1/2

the probability of choosing the fair coin knowing that it showed heads is

P(A/B) = P(A∩B)/P(B)

denoting event A= the coin is fair and event B= the result is heads

P(A∩B) = 1/2*1/2 = 1/4

but since we know now that that the unfair coin is not possible , the probability of choosing heads is altered:

P(B)=probability of choosing heads= probability of choosing A * probability of getting heads from A + probability of choosing B * probability of getting heads from B  = 1/2*1/2+1/2*1 = 3/4

then

P(A/B) = P(A∩B)/P(B)  = (1/4)/(3/4) = 1/3

then the probability is 1/3

8 0
3 years ago
Help me pls I don’t know how to do this
nalin [4]

a=area

b=base

h=height

you have to divide 4.86 with 1.8 it Gives you 2.7

that's your answer .

b=2.7 yd

5 0
2 years ago
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