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olga55 [171]
3 years ago
10

Anybody know ???????????

Mathematics
1 answer:
balandron [24]3 years ago
3 0

Answer:

1. constant: 2

2. you can use slope intercept

3. 4 pounds equal 40 cents

4. because it is linear

Step-by-step explanation:

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Translate into an equation: Five times the sum of a number and six is 48
cricket20 [7]

Hey there! I'm happy to help!

When building equations, the word "is" means "equals".

First, we have the sum of a number and six. You can use any letter to represent the number. I will use n.

(n+6)

We see that this is multiplied by 5. We can just put the 5 next to the parentheses. This shows multiplication.

5(n+6)

Is 48

5(n+6)=48

Have a wonderful day! :D

6 0
4 years ago
you owe 8000 on a motorcycle loan the bank charges a compound interest rato 10.9% poor per year per year if you don't make any p
Andru [333]
I=P(1+(r/n))^nt      
I is the value owed
r is the rate in a decimal
n is the times compounded (annually =1, quarterly =4, monthly =12 etc.)
t is time invested
I=8000(1+(.109/1))^5x1
I=8000(1.109)^5
I=8000(<span>1.67748)
$13419.84</span>
6 0
3 years ago
It cost paisley $9.20 to send 92 text messages how much would it cost to send 110 text messages​
Sergio [31]

Answer:

$11.00

Step-by-step explanation:

Since 92 texts cost her 9.20, each text cost her 10 cents. 110*10 =1100

8 0
3 years ago
Massa says that 540 ÷ 6 = 9. Is he right? Explain how you know using an equation.
Masteriza [31]

Both sides of the equation are not equal, therefore, Massa was wrong.

<h3>How to Evaluate an Equation?</h3>

For an equation to be correct, the values on both sides of the equation must be equal and balance.

Given the expression, 540 ÷ 6 = 9, 540 divided by 6 is 90. 90 is not equal to 9.

Thus, the value on the both sides are not balanced, therefore, Massa is incorrect.

Learn more about equations on:

brainly.com/question/25678139

#SPJ1

7 0
2 years ago
Help me with these please​
olchik [2.2K]

Step-by-step explanation:

(1) y = x e^(x²)

Take derivative with respect to x:

dy/dx = x (e^(x²) 2x) + e^(x²)

dy/dx = 2x² e^(x²) + e^(x²)

dy/dx = (2x² + 1) e^(x²)

Take derivative with respect to x again:

d²y/dx² = (2x² + 1) (e^(x²) 2x) + (4x) e^(x²)

d²y/dx² = (4x³ + 2x) e^(x²) + 4x e^(x²)

d²y/dx² = (4x³ + 6x) e^(x²)

Substitute:

d²y/dx² − 2x dy/dx − 4y

= (4x³ + 6x) e^(x²) − 2x (2x² + 1) e^(x²) − 4x e^(x²)

= 4x³ + 6x − 2x (2x² + 1) − 4x

= 4x³ + 6x − 4x³ − 2x − 4x

= 0

(2) y = sin⁻¹(√x)

sin y = √x

sin²y = x

Take derivative with respect to x:

2 sin y cos y dy/dx = 1

sin(2y) dy/dx = 1

dy/dx = csc(2y)

Take derivative with respect to x again:

d²y/dx² = -csc(2y) cot(2y) 2 dy/dx

d²y/dx² = -2 csc²(2y) cot(2y)

Substitute:

2x (1 − x) d²y/dx² + (1 − 2x) dy/dx

= 2 sin²y (1 − sin²y) (-2 csc²(2y) cot(2y)) + (1 − 2 sin²y) csc(2y)

Use power reduction formula:

= (1 − cos(2y)) (1 − ½ (1 − cos(2y))) (-2 csc²(2y) cot(2y)) + (1 − (1 − cos(2y))) csc(2y)

= (1 − cos(2y)) (1 − ½ + ½ cos(2y)) (-2 csc²(2y) cot(2y)) + cos(2y) csc(2y)

= (1 − cos(2y)) (½ + ½ cos(2y)) (-2 csc²(2y) cot(2y)) + cot(2y)

= (cos(2y) − 1) (1 + cos(2y)) csc²(2y) cot(2y) + cot(2y)

= (cos²(2y) − 1) csc²(2y) cot(2y) + cot(2y)

= -sin²(2y) csc²(2y) cot(2y) + cot(2y)

= -cot(2y) + cot(2y)

= 0

8 0
3 years ago
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