The answer would be 15 but i am not sure what the problem says her answer is. if it is not 15 then her answer is wrong
so, this is a quadratic equation, meaning two solutions, and we have a factored form of it, meaning you can get the solutions by simply zeroing out the f(x).
![\bf \stackrel{f(x)}{0}=-(x-3)(x+11)\implies 0=(x-3)(x+11)\implies x= \begin{cases} 3\\ -11 \end{cases} \\\\\\ \boxed{-11}\stackrel{\textit{\large 7 units}}{\rule[0.35em]{10em}{0.25pt}}-4\stackrel{\textit{\large 7 units}}{\rule[0.35em]{10em}{0.25pt}}\boxed{3}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bf%28x%29%7D%7B0%7D%3D-%28x-3%29%28x%2B11%29%5Cimplies%200%3D%28x-3%29%28x%2B11%29%5Cimplies%20x%3D%20%5Cbegin%7Bcases%7D%203%5C%5C%20-11%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20%5Cboxed%7B-11%7D%5Cstackrel%7B%5Ctextit%7B%5Clarge%207%20units%7D%7D%7B%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D%7D-4%5Cstackrel%7B%5Ctextit%7B%5Clarge%207%20units%7D%7D%7B%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D%7D%5Cboxed%7B3%7D)
so the zeros/solutions are at x = 3 and x = -11, now, bearing in mind the vertex will be half-way between those two, checking the number line, that midpoint will be at x = -4, so the vertex is right there, well, what's f(x) when x = -4?
![\bf f(-4)=-(-4-3)(-4+11)\implies f(-4)=7(7)\implies f(-4)=49 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{vertex}{(-4~~,~~49)}~\hfill](https://tex.z-dn.net/?f=%5Cbf%20f%28-4%29%3D-%28-4-3%29%28-4%2B11%29%5Cimplies%20f%28-4%29%3D7%287%29%5Cimplies%20f%28-4%29%3D49%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20%5Cstackrel%7Bvertex%7D%7B%28-4~~%2C~~49%29%7D~%5Chfill)
Use the following identities:

Also because the angle is in quadrant 3, sin must be negative.
Therefore

Subbing in tan = 0.958
Answer:

Step-by-step explanation:
Let
h -----> the number of hours, Elon works during one 5-day work week
we know that

Elon’s break time must be equal to 1/2 of an hour multiplied by 5 days plus 1/5 multiplied by the total hours h
so

Solve for h
Multiply by 10 both sides to remove the fraction




Hello from MrBillDoesMath!
Answer:
8(v+3) ( -1/2 (sqrt(14) - 4 v) (4 v + sqrt(14)) )
Discussion:
Given
64v^3 + 192v^2 - 56 v - 168
Factor 64v^2 from the first two terms. Factor 56 from the last two terms:
64v^2(v+3) - 56(v + 3) => factor (v+3) from both terms
(v+3) (64v^2 - 56) => factor 8 from both terms in the right ()
8(v+3)(8v^2-7) => factor 8y^2-7
8(v+3) ( -1/2 (sqrt(14) - 4 v) (4 v + sqrt(14)) )
Thank you,
MrB