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goldenfox [79]
3 years ago
6

What is 1/ 3 (x – 10) = -4 (please help )​

Mathematics
1 answer:
horrorfan [7]3 years ago
5 0

Answer:

1/3(x-10)=-4

We move all terms to the left:

1/3(x-10)-(-4)=0

Domain of the equation: 3(x-10)!=0

We add all the numbers together, and all the variables

1/3(x-10)+4=0

We multiply all the terms by the denominator

4*3(x-10)+1=0

Wy multiply elements

12x(x+1=0

Step-by-step explanation:

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5 0
3 years ago
James measured a piece of construction paper to be 6 3/4 inches wide and 9 2/3 inches long. What is the area of the piece of con
ivolga24 [154]

Answer:

The area of the piece of construction paper is \frac{261}{4} inches^2

Step-by-step explanation:

Length of construction paper =6 \frac{3}{4} inches

                                                 =\frac{27}{4} inches

Width of construction paper = 9 \frac{2}{3} inches

                                              = \frac{29}{3} inches

Area of construction paper =Length \times Width

Area of construction paper = \frac{27}{4}  \times \frac{29}{3}

                                             = \frac{261}{4} inches^2

Hence the area of the piece of construction paper is \frac{261}{4} inches^2

7 0
3 years ago
What will the horizontal cross of a cone be​
erma4kov [3.2K]

Answer:

Step-by-step explanation:

A horizontal cross section of a cone will be circle

5 0
3 years ago
30 Points!!
neonofarm [45]

Answer:

  multiply the left side of the constant vector by the inverse matrix

Step-by-step explanation:

The matrix equation ...

  AX = B

is solved by left-multiplying by the inverse of A:

  A⁻¹AX = A⁻¹B

  IX = A⁻¹B . . . . . the result of multiplying A⁻¹A is the identity matrix

  X = A⁻¹B . . . . . B needs to be multiplied by the inverse matrix

\left[\begin{array}{c}x&y\end{array}\right] = \left[\begin{array}{cc}-4&1\\3&2\end{array}\right]^{-1}\left[\begin{array}{c}9&7\end{array}\right]=\dfrac{1}{11}\left[\begin{array}{cc}-2&1\\3&4\end{array}\right]\left[\begin{array}{c}9&7\end{array}\right]=\left[\begin{array}{c}-1&5\end{array}\right]

4 0
3 years ago
The flaplike lateral wall of each atrium is called the
pantera1 [17]
You mean like the tricuspid and mitral (bicuspid) valves?
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