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amm1812
3 years ago
14

Is it prime or polynomial

Mathematics
1 answer:
bogdanovich [222]3 years ago
7 0
  The expression:  4x² + 38x + 70  ;  is a polynomial expression.
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14x+10y=72 14x+4y=96 Solve the following system of equations using any method
Anarel [89]
    14x + 10y = 72
    14x +   4y = 96
                6y = -24
                 6       6
                  y = -4
    14x + 10y = 72
14x + 10(-4) = 72
       14x - 40 = 72
             + 40 + 40
              14x = 112
               14      14
                  x = 8
            (x, y) = (8, -4)
5 0
3 years ago
Logio1,000 =<br> 1/3<br> 100
Vera_Pavlovna [14]

Answer:

the answer is 1/3

Step-by-step explanation:

HOPE THIS HELPS!!

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8 0
3 years ago
WILL GIVE BRAINLIEST 27 points
tangare [24]
It is not direct variation because it does not follow the equation 
y = slopex
THE points do not make the equation true . 

3 0
3 years ago
Read 2 more answers
SOMEONE EASE ANSWER NUMBER 4?
nlexa [21]

On analyzing the question we can say that the angle ∠JKM of the triangle ΔJKL would be 42 as line MK bisects ∠JKL into ∠JKM & ∠MKL.

From the question it follows that line MK bisects angle ∠JKL into ∠JKM & ∠MKL where M is the point in the interior of ∠JKL.

Therefore, as we have given  m∠JKL = 84 & m∠MKL  = 42

and we have to find m∠JKM , we will simply write the equation as follow

m∠JKL = m∠JKM + m∠MKL

Inserting values we get,

84 = m∠JKM + 42

m∠JKM = 42

Hence, angle m∠JKM  of the triangle ΔJKL is  42.

Learn more about questions related to triangles and their angles here

brainly.com/question/13273388

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5 0
2 years ago
A Pew Internet poll asked cell phone owners about how they used their cell phones. One question asked whether or not during the
EastWind [94]

Answer:

a) \hat p=\frac{471}{1024}=0.460

The standard error is given by:

SE= \sqrt{\frac{\hat p(1-\hat p)}{n}}=\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0156

And the margin of error is given by:

ME=z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}=1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0305

b) The 99% confidence interval would be given by (0.429;0.491)

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Data given and notation  

n=1024 represent the random sample taken    

X=471 represent the people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering

\hat p=\frac{471}{1024}=0.460 estimated proportion of people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering    

p= population proportion of people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering

Part a

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

The standard error is given by:

SE= \sqrt{\frac{\hat p(1-\hat p)}{n}}=\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0156

And the margin of error is given by:

ME=z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}=1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0305

Part b

If we replace the values obtained we got:

0.460-1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.429

0.460+1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.491

The 99% confidence interval would be given by (0.429;0.491)

8 0
3 years ago
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