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inysia [295]
3 years ago
8

Line L has equation 2x - 3y = 5.

Mathematics
1 answer:
Misha Larkins [42]3 years ago
7 0
Y = 2/3x - 12

You can get this because they will have the same slopes and you can solve for the intercept.
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Mike jogged 6 laps around a 0.25 mile track on Monday and 7 laps on Tuesday. How many miles did he jog on Monday and Tuesday com
crimeas [40]

Answer: 3.25 miles

Step-by-step explanation:

6 + 7 = 13

13 x .25 = 3.25

3 0
3 years ago
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Compare & Contrast: What is different about complementary and supplementary angles? What is the same?​
kirza4 [7]

Complementary: When two angles add up to 90 degrees

Supplementary: When two angles add up to 180 degrees

Similarities are both involve two angles, the difference is the total degrees they add up to.

3 0
3 years ago
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How do I solve 2x-3y=-1. y=x-1
nlexa [21]
Hello!

You can put in y for the first equation

2x - 3(x - 1) = -1

Distribute the -3

2x - 3x + 3 = -1

Combine like terms

-x + 3 = -1

Subtract 3 from both sides

-x = -4

Since x is negative we can multiply both sides by -1 to make x positive

x = 4

We can put x into the second equation to get y

y = 4 - 1

y = 3

The answers are x = 4 and y = 3

Hope this helps!
7 0
4 years ago
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A bag contains 12 red marbles the ratio of red marbles to blue marbles is 4:3 find the number of blue marbles in the bag
yKpoI14uk [10]
9 blue marbles are in the bag
4 0
3 years ago
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Using the quadratic formula to solve 4x2 – 3x + 9 = 2x + 1, what are the values of x? StartRoot 1 plus-or-minus StartRoot 159 En
castortr0y [4]

For this case we have that a quadratic equation is of the form:

ax ^ 2 + bx + c = 0

The roots are given by:

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}

We have the following equation:

4x ^ 2-3x + 9 = 2x + 1\\4x ^ 2-3x-2x + 9-1 = 0\\4x ^ 2-5x + 8 = 0

We look for the roots:

x = \frac {- (- 5) \pm \sqrt {(- 5) ^ 2-4 (4) (8)}} {2 (4)}\\x = \frac {5 \pm \sqrt {25-128}} {8}\\x = \frac {5 \pm \sqrt {-103}} {8}

We have to:

i ^ 2 = -1

So:

x = \frac {5 \pm \sqrt {103i ^ 2}} {8}\\x = \frac {5 \pm i \sqrt {103}} {8}

We have two imaginary roots:

x_ {1} = \frac {5 \ + i \sqrt {103}} {8}\\x_ {2} = \frac {5 \ -i \sqrt {103}} {8}

Answer:

x_ {1} = \frac {5 \ + i \sqrt {103}} {8}\\x_ {2} = \frac {5 \ -i \sqrt {103}} {8}

8 0
4 years ago
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