Given that the perimeter of rhombus ABCD is 20 cm, the length of the sides will be: length=20/4=5 cm the ratio of the diagonals is 4:3, hence suppose the common factor on the diagonals is x such that: AC=4x and BD=3x using Pythagorean theorem, the length of one side of the rhombus will be: c^2=a^2+b^2 substituting our values we get: 5²=(2x)²+(1.5x)² 25=4x²+2.25x² 25=6.25x² x²=4 x=2 hence the length of the diagonals will be: AC=4x=4×2=8 cm BD=3x=3×2=6 cm Hence the area of the rhombus wll be: Area=1/2(AC×BD) =1/2×8×6 =24 cm²
3 weeks = 21 days Let Jerrad's vacation be X then Max's be 2X and Wesley's 4X X+2X+4X=21 7X=21 devide by 7 X=3 so Jerrad had 3 days vacation 2*3= 6 Max had 6 days 4*3=12 Wesley had 12 days vacation
