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uysha [10]
3 years ago
6

ABCD rhombus, AC:BD = 4:3 Perimeter ABCD = 20 cm Find: Area of ABCD

Mathematics
1 answer:
AlladinOne [14]3 years ago
6 0
Given that the perimeter of rhombus ABCD is 20 cm, the length of the sides will be:
length=20/4=5 cm
the ratio of the diagonals is 4:3, hence suppose the common factor on the diagonals is x such that:
AC=4x and BD=3x
using Pythagorean theorem, the length of one side of the rhombus will be:
c^2=a^2+b^2
substituting our values we get:
5²=(2x)²+(1.5x)²
25=4x²+2.25x²
25=6.25x²
x²=4
x=2
hence the length of the diagonals will be:
AC=4x=4×2=8 cm
BD=3x=3×2=6 cm
Hence the area of the rhombus wll be:
Area=1/2(AC×BD)
=1/2×8×6
=24 cm²
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3 years ago
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leonid [27]
PART A
Change the fractions into improper fractions
pablo - rosa = 4 4/9 - 3 5/12
pablo - rosa = 40/9 - 41/12

Equalize the denominator of the fractions
I equalize them to 36. If the denominator 9 is multiplied by 4, so is the numerator. If the denominator 12 is multiplied by 3, so is the numerator.
pablo - rosa = 40/9 - 41/12
pablo - rosa = (40 × 4)/(9 × 4) - (41 × 3)/(12 × 3)
pablo - rosa = 160/36 - 123/36
pablo - rosa = 37/36

Change it to mixed fraction
pablo - rosa = 37/36
pablo - rosa = 1 1/36

Pablo has 1 1/36 quarts more than Rosa

PART B
Calculate the iced tea Pablo gave to Rosa
Change into proper fraction/improper fraction
iced tea given = 15% × 4 4/9
iced tea given = 15/100 × 40/9
iced tea given = 600/900
iced tea given = 2/3

Calculate Pablo's iced tea after giving
Pablo's = 40/9 - 2/3
Pablo's = 40/9 - (2 × 3)/(3×3)
Pablo's = 40/9 - 6/9
Pablo's = 34/9
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Calculate Rosa's iced tea
Rosa's = 41/12 + 2/3
Rosa's = 41/12 + (2 × 4)/(3 × 4)
Rosa's = 41/12 + 8/12
Rosa's = 49/12
Rosa's = 4 1/12

Pablo has 3 7/9 quarts and Rosa has 4 1/12 quarts
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Gekata [30.6K]

Answer:

b

Step-by-step explanation:

The median of a triangle is a line that from the vertex touches the middle lets eliminate options

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<u>SO THE CORRECT ANSWER IS B</u>

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