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3 years ago

ABCD rhombus, AC:BD = 4:3 Perimeter ABCD = 20 cm Find: Area of ABCD

1 answer:

6 0

Given that the perimeter of rhombus ABCD is 20 cm, the length of the sides will be:
length=20/4=5 cm
the ratio of the diagonals is 4:3, hence suppose the common factor on the diagonals is x such that:
AC=4x and BD=3x
using Pythagorean theorem, the length of one side of the rhombus will be:
c^2=a^2+b^2
substituting our values we get:
5²=(2x)²+(1.5x)²
25=4x²+2.25x²
25=6.25x²
x²=4
x=2
hence the length of the diagonals will be:
AC=4x=4×2=8 cm
BD=3x=3×2=6 cm
Hence the area of the rhombus wll be:
Area=1/2(AC×BD)
=1/2×8×6
=24 cm²

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3 years ago

What does X= in 5/8 x + 1/16 x= 11/16?

Vesna [10]

Answer:

x = 1

Step-by-step explanation:

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3 years ago

PLEASE ANSWER QUICK A manufacturing facility pays its employees an average wage of $4.50 an hour with a standard deviation of 50

evablogger [386]

Answer:

B.77.4%

Step-by-step explanation:

Mean wage (μ) = $4.50

Standard deviation (σ) = $0.50

For nay given salary X, the z-score is given by:

$z=\frac{X-\mu}{\sigma}$

For X = $3.75, the z-score is:

$z=\frac{3.75-4.50}{0.50}\\z=-1.5$

For X = $5.00, the z-score is:

$z=\frac{5.00-4.50}{0.50}\\z=1$

A z-score of -1.5 corresponds to the 6.68th percentile, while a score of 1 corresponds to the 84.13th percentile. Therefore, the percentage of workers getting paid between $3.75 and $5.00 an hour is:

$P=84.13-6.68\\P=77.45\%$

The answer is alternative B.77.4%

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3 years ago

A Ski resort tracks the proportion of seasonal employees who are rehired each season. Rehiring a seasonal employee is beneficial

DaniilM [7]

The test statistic z will be equal to -0.946 and it shows that there is no significant difference in the proportion of rehires between full time and part time.

Given sample sizes of 833 and 386 and result of samples 434 and 189.

$n_{1} =833, n_{2}=386$

Proportion of full time=434/833=0.52

Proportion of part time=189/386=0.49.

Difference in proportion =0.52-0.49

$H_{0}:$ TTF- i∈ rho=0

$H_{1}:$ TTF+i∈ rho≠0.

Mean of difference=0.03

Z=(X-μ)/σ

σ= $\sqrt{0.4517/447}$

=0.0317

σ=0.0317

z=(0-0.03)/0.0317

=-0.03/0.0317

=-0.317

p value will be =0.1736.

Because p value is greater than 0.01 so we will accept the null hypothesis which shows that there is no significant difference in the proportions.

Hence there is no significant difference in the proportion of rehires between full time and part time.

Learn more about z test at brainly.com/question/14453510

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2 years ago

Fantastic Middle School is building a park, in the shape of a square, with an area of 256 square feet. How much fence do they ne

frez [133]

A = a^2.....where " a " is the size of 1 side
A = 256

256 = a^2...take sqrt of both sides, eliminating the ^2
sqrt 256 = a
16 = a

so each side is 16 ft....now we find the perimeter
P = 4a....where " a " is the size of each side
P = 4(16)
P = 64.......so they will need 64 ft of fencing <===

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3 years ago