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3 years ago

When rounding to the nearest hundred, which of the following numbers round to 400?

2 answers:

6 0

When rounding numbers up or down, you need to look at the number in the place to the right of the place you are rounding to.

You have been asked to round to the nearest hundred (3rd place from the right)

Look one place to the right of the hundred place (the ten's place in this instance). If it is 4 or less, you will leave the hundred's digit as is and fill in the tens and ones places with a zero (this is called rounding down).

If it is 5 or higher, you will "round up" the digit in the hundred's place to the next hundred.

348 has a 4 in the tens place - so we will "round down" by leaving the hundred digit and placing zeros in the tens and ones. (300)

452 rounds up to 500 (because of the 5 in the tens place)

325 rounds down...

423 rounds down...

351 rounds up to ... 400! We found our answer

445 rounds down...

shepuryov [24]3 years ago

4 0

The answer is 423 since it's the closest number to 400 from all the numbers listed above.

The numbers 351 and 445 would also round to 400 but they are not the closest ones.

Hope it helped,

BioTeacher101

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Model the following problem with a quadratic equation. Then solve. Find the length of a side of a square with an area of 75 ft2.

Vaselesa [24]

Answer:

x = 8.6603 m

Step-by-step explanation:

If x is the length of a side of the square, the area of the square will be x^2.

So, if the area of the square is 75 ft2, we can formulate the quadratic equation:

x^2 = 75

Now, solving the equation, we just need to make the square root of 75:

x = sqrt(75) = ±8.6603

x1 = 8.6603

x2 = -8.6603

Now, as x represents the length of a side of the square, and measurements can't be negative, we take only the positive value, so:

x = 8.6603 m

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2 years ago

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saul85 [17]

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Step-by-step explanation:

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2 years ago

100 points!!! Pre calculus. I need helpppppppppp

Fantom [35]

Answer:

We have function,

$y = 3 - 6 \sin {}^{} (2x + \frac{\pi}{2} )$

Standard Form of Sinusoid is

$y = - 6 \sin(2x + \frac{\pi}{2} ) + 3$

Which corresponds to

$y = a \sin(b(x + c)) + d$

where a is the amplitude

2pi/b is the period

c is phase shift

d is vertical shift or midline.

In the equation equation, we must factor out 2 so we get

$y = - 6(2(x + \frac{\pi}{4} )) + 3$

Also remeber a and b is always positive

So now let answer the questions.

a. The period is

$\frac{2\pi}{ |b| }$

$\frac{2\pi}{ |2| } = \pi$

So the period is pi radians.

b. Amplitude is

$| - 6| = 6$

Amplitude is 6.

c. Domain of a sinusoid is all reals. Here that stays the same. Range of a sinusoid is [-a+c, a-c]. Put the least number first, and the greatest next.

So using that<em> rule, our range is [6+3, -6+3]= [9,-3] So our range</em> is [-3,9].

D. Plug in 0 for x.

$3 - 6 \sin((2(0) + \frac{\pi}{2} )$