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aleksklad [387]
3 years ago
10

Fill in the blank. The diagonals of a rhombus are __________________.

Mathematics
2 answers:
Mandarinka [93]3 years ago
8 0
The diagonals of a rhombus are : 
Perpendicular and bisect each other
Opposite angles of a rhombus have equal measure

hope this helps
Doss [256]3 years ago
4 0

Answer:

Perpendicular and bisect each other

Step-by-step explanation:


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Eric ordered 6 tacos and 1 large pop. The large pop costs $2.00 and the total cost of his order was
pshichka [43]

Answer: 6x + $2= $21.50

Step-by-step explanation:

To make an equation first we are going to give the cost of each taco the variable x since we don't know what it is. Then we will combine 6 multiplied by x to get 6x and add it to $2 to get $21.50 so the equation will be 6x + $2= $21.50. First we subtract 2 from both sides of the equation which makes the equation become 6x= $19.50. Then we divide both sides of the equation by 6 and get x=$3.25. This means that each taco cost $3.25.

5 0
3 years ago
Draw any two convex pentagons. For each of them measure the sum of its interior angles using a protractor. Explain the result of
m_a_m_a [10]
Shouldn;t it be 540?
4 0
3 years ago
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A 40-m-long chain hangs vertically from a cylinder attached to a winch. Assume there is no friction in the system and the chain
daser333 [38]

Answer:

a) W₁ = 78400 [J]

b)Wt = 82320 [J]  

Step-by-step explanation:

a) W = ∫ f*dl      general expression for work

If we have a chain with density of 10 Kg/m, distributed weight would be

9.8 m/s² * 10 kg   = mg

Total length of th chain is 40 m, and the function of y at any time is

f(y) = (40 - y ) mg   where ( 40 - y ) is te length of chain to be winded

At the beggining we have to wind 40 meters   y = 0 at the end of the proccess  y = 40 and there is nothing to wind then:

f(y) = mg* (40 - y )

W₁ =  ∫f(y) * dy    ⇒ W₁ = ∫₀⁴⁰ mg* (40 - y ) dy  ⇒ W₁ = mg [ ∫₀⁴⁰ 40dy - ∫₀⁴⁰ ydy

W₁ = mg [ 40*y |₀⁴⁰   -  1/2 * y²  |₀⁴⁰    ⇒  W₁ = mg* [ 40*40 - 1/2 (40)² ]

W₁ = mg * [1/2]     W₁ = 10*9,8* ( 800 )

W₁ = 78400 [J]

b) Now we can calculate work to do if we have a 25 block and the chain is weightless

W₂ = ∫ mg* dy     ⇒    W₂  = ∫₀⁴⁰ mg*dy   ⇒    W₂  = mg y |₀⁴⁰

W₂ = mg* 40   = 10*9.8* 40  

W₂ = 3920 [J]

Total work

Wt = W₁  +  W₂        ⇒    Wt = 78400 + 3920

Wt = 82320 [J]

6 0
3 years ago
1. -10+4 =<br> 2. -7+11=<br> 3. -8+7=
Setler [38]

1. -6

2. 4

2. -1

The positive numbers will out rule the negative number. It's sort of like placing blocks over another set of blocks. :)

5 0
3 years ago
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Divide the complex numbers
Otrada [13]

Answer:

1/4 - 1/3i

Step-by-step explanation:

(4+3i)(-i) / 12i(-i)

= 3 - 4i / 12

3 0
3 years ago
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