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Anuta_ua [19.1K]
3 years ago
5

Endpoint: (-4,-10), midpoint (5.-8) What is the other endpoint?

Mathematics
1 answer:
timofeeve [1]3 years ago
3 0

Answer:

Step-by-step explanation:

(x - 4)/2 = 5

x - 4 = 10

x = 14

(y - 10)/2= -8

y - 10 = -16

y = -6

(14, -6)

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Jackson can lay 6000 ft² of tile in 3 h.
Juli2301 [7.4K]

Answer:

2000 ft^2/h

Step-by-step explanation: Because 6000 divided by 3 is 2000


4 0
3 years ago
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Please help me with 13 and 15 asap
Law Incorporation [45]
Gosh, I've done this problem before. Let's start with 13. In this problem, we're basically just skip counting. For example, in the roses row, in the second bouquet, we know we have to add 4 more flowers, so we can document 8. Continue to skip count for both. For 15, we would have about 96 more movie posters remaining, making our ratio 96:x. So, 96:x = 120:100. Therefore, x would equal 80- as 96:80 equals 120:100. If she needs 80 and already had 100, she should sell 20 posters. Hope this helped.
3 0
2 years ago
Price of 1kg sugar is Rs. 100 calculate the price of 150g sugar?​
Wewaii [24]

Answer:Rs15

Step-by-step explanation:

150g=150/1000=0.15kg

1kg cost Rs100

0.15kg cost =100 x 0.15=15

150g cost Rs15

3 0
2 years ago
Find a compact form for generating functions of the sequence 1, 8,27,... , k^3
pantera1 [17]

This sequence has generating function

F(x)=\displaystyle\sum_{k\ge0}k^3x^k

(if we include k=0 for a moment)

Recall that for |x|, we have

\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k

Take the derivative to get

\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k

\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k

Take the derivative again:

\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k

\implies\displaystyle\frac{x+x^2}{(1-x)^3}=\sum_{k\ge0}k^2x^k

Take the derivative one more time:

\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k

\implies\displaystyle\frac{x+4x^3+x^3}{(1-x)^4}=\sum_{k\ge0}k^3x^k

so we have

\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}

5 0
3 years ago
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tia_tia [17]

Answer: D

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You save the most money with option D. Not in the long run though

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