The equation of line perpendicular to x-2y=-16 passing through (9,8) is: y=-2x+26
Step-by-step explanation:
Given

The equation is in slope-intercept form, the coefficient of x will be the slope of given line. The slope is: 1/2
As the product of slopes of two perpendicular lines is -1.

Slope intercept form is:

Putting the value of slope
y=-2x+b
To find the value of b, putting (9,8) in the equation

Putting the values of b and m

Hence,
The equation of line perpendicular to x-2y=-16 passing through (9,8) is: y=-2x+26
Keywords: Equation of line, Slope-intercept form
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Answer:
Step-by-step explanation

⇒ 80 + ( 2 * 0.01 ) + ( 9 * 0.001 )
⇒ 80 + 0.02 + 0.009
= 80.029
Polygon HJKL has vertices H(-3, 4), J(2, 6), K(2, 1), and L(-3, -1). What are the slopes of sides HJ, JK, KL, and LH and how wou
aleksklad [387]
<span> the slopes of sides HJ, JK, KL, and LH and how would you classify HJKL?</span>
<span> Move to the right side of the </span>equation<span> by adding to both sides.</span>
Answer: 59
Step-by-step explanation: