What is the square root of 147?

Mathematics

1 answer:

olga nikolaevna [1]3 years ago

7 0

The square root of 147 when rounded to the nearest tenth is about 12.1

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Differentiate f and find the domain of f. (enter the domain in interval notation.)f(x) = ln(x2 − 12x)derivative f '(x) = 2x−12x2

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f(x) is undefined when x² - 12x = x(x - 12) = 0
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Answer:
The derivative is
$f'(x) = \frac{2x-12}{x^{2}-12x}$
The domain is
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Cheese: $4\frac{3}{8}$
Milk: $1\frac{2}{3}$
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Step-by-step explanation:

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