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Svetlanka [38]
3 years ago
10

Stacia was 5 feet tall on her 12th birthday and 5 feet 3 inches tall on her 13th birthday.

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
5 0

5%

Convert feet to inches by multiplying 5 by 12 (12 inches in 1 foot) 5×12=60

We know 5 feet is 60 inches so 5 feet 3 inches is 63 inches (60+3)

To find percent increase do 63÷60=1.05

1.05=5% increase

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1. Joshua has a ladder that is 12 ft long. He will lean the ladder against a vertical wall. For safety reasons, he wants the ang
marishachu [46]
Let h=height where top of ladder touches wall and x be distance from wall to bottom of ladder...

tana=h/x

a=arctan(h/x)  and a≤75

arctan(h/x)≤75  now taking tan of both sides :P

h/x≤tan75 now we have an ugly x value that we need to get rid of:

Using the pythagorean theorem we know:

144=x^2+h^2, x^2=144-h^2, x=√(144-h^2)  now we can use this in our inequality for x

h/√(144-h^2)≤tan75

h^2/(144-h^2)≤(tan75)^2

h^2≤144(tan75)^2-h^2(tan75)^2

h^2+h^2(tan75)^2≤144(tan75)^2

h^2(1+(tan75)^2)≤144(tan75)^2

h^2≤[144(tan75)^2]/(1+(tan75)^2)

h^2≤134.353829

h≤11.5911

So he cannot have the top of the ladder 11.8 ft above the ground and not exceed a 75° angle with the ground.

I worked it the hard way just to go through the process.  However we could have used a simple trig function to see that maximum height of the top of the ladder....

sin75=h/12

h=12sin75

h≈11.59 ft.  That would be the maximum height given that we did not want to exceed 75° with the ground.




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3 years ago
Can someone help me with this. Will Mark brainliest.
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Answer:

gv   hjbiuhkjbOn the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.

Step-by-step explanation:

7 0
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