Given:
Base length of triangle = 40 units
Height of triangle = 9 units
Length of hypotenuse of triangle = 41 units
To find:
Find the value of Tan A
Steps:
Tan of an angle is equal to the opposite length by adjacent length.
So,
Tan A = 
Tan A = 
Tan A = 0.225
Therefore, the exact value of Tan A is 0.225.
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Answer:
Rhombus
Step-by-step explanation:
it's like a diamond but it's a little bit thicker
Let 's' represent the amount of sales.
Plan 1:


Plan 2:


Equating the two plans together and solving for the amount of sales,

Collecting like terms,

Divide both sides by 0.08,

Hence, the amount of sales is $8,750.
Answer:
Approximate probability that
is less than 2 = 0.1515
Step-by-step explanation:
Given -
Mean
= 2.2
Standard deviation
= 1.4
Sample size ( n ) = 52
Let
be the mean of accidents per week at the intersection during one year (52 weeks) .
probability that
is less than 2 =
=
Putting 
=
( Using Z table )
= 0.1515
Answer:
25
Explanation:
In order to solve this the easiest way you can use equivalent fractions.

Since 4 times 5 equals 20 we can multiply 5 times 5 to get our answer.

25 is the answer. But, if we couldn't have gotten to 20 through the multiplication we could use a proportion. That would look like the initial problem but instead of a "?" we would use a variable. I will use <em>t</em> for total.

So now we have our problem set up. The next step is to cross multiply. 4 by <em>t</em> and 5 by 20.

And now we can solve it like a normal algebra problem.

Either way, we get 25.