Hello!
The correct answer would be: D. Should not exceed a vehicle's rated load or life capacity.
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Answer:
- Divide the resources into three parts using the corresponding process 1, process 1, and process 2 formats to maximize the use of the resources.
- Get the expected revenue by calculating the product of the total perfume in ounce and the price of an ounce of perfume.
- Increase the advertisement hours of the product.
- subtract the advert fee from the generated revenue to get the actual revenue.
- subtract the cost of production from the actual revenue to get the actual profit.
Explanation:
The get maximum profit, all the resources must be exhausted in production. The labor is divided into a ratio of 1:1:2 ( which is 5000, 5000, 1000), while the chemical units are in the ratio of 2:2:3 (10000,10000,15000). This would produce in each individual processes; 15000, 15000 and 25000 oz, which is a total of 55000 oz of perfume.
The expected revenue is $275000. If 1000oz from the 55000oz of perfume is sold without advertisement, model Jenny's awareness of the perfume increases the demand by 200oz per hour, therefore, 24hours would field 4800oz demanded, which would only take 270 hours to distribute all remaining perfumes.
The cost of production would be $130000 for labor and chemical resources plus the advert cost of $27000 ( 270 hours by 100) which is a total cost of $157000. The actual profit is $118000 ( $275000 - $157000).
Answer: E. Use a RESTful architecture for both, send the ID through a POST, and ping the service with a GET until a response is available.
Explanation:
Since there are two microservices that need to communicate with each other without holding up a thread on either end, the communication framework should be used is a RESTful architecture for both, send the ID through a POST, and ping the service with a GET until a response is available.
REST is a software architectural style which is used in defining the set of rules that be used for the creation of web services. The REST architecture allows requesting systems to be able to access and manipulate web resources.
I'm a little confused about the question, but if you're asking how many points you need to ask a question, the minimum is 10.
Answer:An initial condition is an extra bit of information about a differential equation that tells you the value of the function at a particular point. Differential equations with initial conditions are commonly called initial value problems.
The video above uses the example
{
d
y
d
x
=
cos
(
x
)
y
(
0
)
=
−
1
to illustrate a simple initial value problem. Solving the differential equation without the initial condition gives you
y
=
sin
(
x
)
+
C
.
Once you get the general solution, you can use the initial value to find a particular solution which satisfies the problem. In this case, plugging in
0
for
x
and
−
1
for
y
gives us
−
1
=
C
, meaning that the particular solution must be
y
=
sin
(
x
)
−
1
.
So the general way to solve initial value problems is: - First, find the general solution while ignoring the initial condition. - Then, use the initial condition to plug in values and find a particular solution.
Two additional things to keep in mind: First, the initial value doesn't necessarily have to just be
y
-values. Higher-order equations might have an initial value for both
y
and
y
′
, for example.
Second, an initial value problem doesn't always have a unique solution. It's possible for an initial value problem to have multiple solutions, or even no solution at all.
Explanation: