3 years ago

2PLEAAAAAASEEEE HELP! ILL GIVE BRAINLIEST I PROMISEEEEE!!!!!

1 answer:

7 0

Answers:

1.B

2.C

3.D

4.A

5.B

6.C

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galina1969 [7]

First, we can use the points (4,3) and (20,15) to find the slope of the line:

$\begin{gathered} s=\frac{m_2─m_1}{j_2─j_1}=\frac{15─3}{20─4}=\frac{12}{16}=\frac{3}{4} \\ s=\frac{3}{4} \end{gathered}$

Now we can find the relation function using the point (4,3) and the slope s=3/4

$\begin{gathered} m─m_1=s(j─j_1) \\ \Rightarrow m─3=\frac{3}{4}(j─4)=\frac{3}{4}j─(\frac{12}{4})=\frac{3}{4}j─3 \\ m=\frac{3}{4}j \end{gathered}$

therefore, the equation to describe the relationship between J and M is m=3/4j

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Tasya [4]

Answer:

Step-by-step explanation:

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mote1985 [20]

Answer:

521.1

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VashaNatasha [74]

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telo118 [61]

Answer: 3x

Step-by-step explanation:

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