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o-na [289]
3 years ago
12

The answer is A the answer is a because it is asking how.....___________________________________________________________________

_________________________________________________________________________________________________________________________________________________________________________________________________________________________________________
Mathematics
1 answer:
Dmitrij [34]3 years ago
5 0
A was A for the fun of it also I’m just putting anything down cause I put no question
You might be interested in
7b+12=5b what is the value for b?
likoan [24]

Answer:

B = -6

Step-by-step explanation:

7b + 12 = 5b

12 = -2b

-6 = b

Hope this helps. Pls give brainliest.

6 0
2 years ago
Please help find the Measure of 1 step by step
maks197457 [2]

Answer: 112°

Step-by-step explanation:

a straight line only has 180° at all times so it is a matter of subtraction. 180-68 is 112° so from there you can find #2 as 68°, #3 as 90° and #4 as 90°, and so on.

3 0
3 years ago
How many terms are there in the sequence 1, 8, 28, 56, ..., 1 ?
BabaBlast [244]

Answer:

9 terms

Step-by-step explanation:

Given:  

1, 8, 28, 56, ..., 1

Required

Determine the number of sequence

To determine the number of sequence, we need to understand how the sequence are generated

The sequence are generated using

\left[\begin{array}{c}n&&r\end{array}\right] = \frac{n!}{(n-r)!r!}

Where n = 8 and r = 0,1....8

When r = 0

\left[\begin{array}{c}8&&0\end{array}\right] = \frac{8!}{(8-0)!0!} = \frac{8!}{8!0!} = 1

When r = 1

\left[\begin{array}{c}8&&1\end{array}\right] = \frac{8!}{(8-1)!1!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8

When r = 2

\left[\begin{array}{c}8&&2\end{array}\right] = \frac{8!}{(8-2)!2!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} =2 8

When r = 3

\left[\begin{array}{c}8&&3\end{array}\right] = \frac{8!}{(8-3)!3!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56

When r = 4

\left[\begin{array}{c}8&&4\end{array}\right] = \frac{8!}{(8-4)!4!} = \frac{8!}{4!3!} = \frac{8 * 7 * 6 * 5 * 4!}{4! *4*3* 2 *1} = \frac{8 * 7 * 6*5}{4*3 *2 *1} = 70

When r = 5

\left[\begin{array}{c}8&&5\end{array}\right] = \frac{8!}{(8-5)!5!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56

When r = 6

\left[\begin{array}{c}8&&6\end{array}\right] = \frac{8!}{(8-6)!6!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} = 28

When r = 7

\left[\begin{array}{c}8&&7\end{array}\right] = \frac{8!}{(8-7)!7!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8

When r = 8

\left[\begin{array}{c}8&&8\end{array}\right] = \frac{8!}{(8-8)!8!} = \frac{8!}{8!0!} = 1

The full sequence is: 1,8,28,56,70,56,28,8,1

And the number of terms is 9

3 0
3 years ago
Which of the following would be equivalent to 92 ⋅ 96? 9 to the 8th power over 9 to the 7th power 92 ⋅ 97 9 to the 10th power ov
san4es73 [151]
9^2 × 9^6=9^10/9^2

When multiplying exponents, if the bases are the same you add the exponents.
9^2 × 9^6 = 9^(2+6)=9^8

When dividing exponents, I'd the bases are the same you subtract the bottom exponent from the top.
9^10/9^2=9^(10-2)=9^8

9^8=9^8

Solution: 9^10 over 9^2
3 0
3 years ago
Read 2 more answers
Which statement describes the image?
boyakko [2]

Answer:

d.) none are correct

Step-by-step explanation:

it should be reflection over the y-axis then reflection over the x-axis

3 0
3 years ago
Read 2 more answers
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