There is no sum for this geometric series. it diverges rather than converges due to the absolute value of the common ratio (r), which is -3, being 3. for a geometric series to have a sum (to converge), the absolute value of r must be less than 1.
(you find r by dividing a2/a1, a3/a2, etc.)
hope this helps
Answer:
31 u jest read it
Step-by-step explanation:
<span><span>(<span><span><span><span><span>4<span>x<span>−2</span></span></span><span>y^3</span></span>x</span></span><span>y<span>−4</span></span></span>)</span><span>−2</span></span><span>
=<span><span><span><span><span>x6</span><span>y^8/</span></span><span>16<span>y^6</span></span></span></span></span></span><span>
=<span><span><span><span>x^6</span><span>y^2/</span></span><span>16
Hope this helps:)
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Answer:
n o
Step-by-step explanation:
I refuse to help. punish me and put me in the toilet
jk lol
Answer:
it costs 2 dollars :)
Step-by-step explanation:
