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son4ous [18]
3 years ago
10

PLEASE HELP!! FILL IN THE BLANK MATH QUESTION, ONLY ANSWER IF YOU KNOW THE CORRECT ANSWER CAUSE MY GRADE DEPENDS ON IT

Mathematics
2 answers:
vagabundo [1.1K]3 years ago
7 0
First blank: sin. C = h/a
The ratio for sin. is opposite (the height) over hypotenuse (a).

Second blank: Area = (1/2)b(a sin. C)
In this substitution, we are substituting the value of h into the traditional area of a triangle formula.

Third Blank: Area = (1/2)ab(sin C)
We are using the commutative property to move the position of a. 
Hope this helps and good luck in your classes!
lozanna [386]3 years ago
3 0
The altitude of the triangle would be another line added to the triangle which bisects angle B. We are calling this side h. Looking at the right triangle this added side forms, with respect to angle C, "h" would be the opposite side and "a" would be  the hypotenuse. We know that sin∅ = opposite/hypotenuse, so the first blank is:

sinC = h/a

For the second blank, we need to redefine side h. We know sinC = h/a, so let's rearrange that to solve for h:

h = a*sinC

If we substitute a*sinC for h is 0.5*b*h, we get:

Area = 1/2 * b(asinC)

Finally, according to the commutative property of multiplication, the order of terms being multiplied doesn't matter. Therefore the final blank is:

Area = 1/2 * ab(sinC)
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Levart [38]
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4 0
3 years ago
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a recipe called for the ratio of sugar to flour to be 5 to 1 if you use 35 ounces of sugar how many ounces of flour do you need
den301095 [7]
7

The answer is 7 
The ratio would look like 35/7
4 0
3 years ago
Let Ebe the set of all even positive integers in the universe Zof integers, and XE : Z R be the characteristic function of E.
AnnZ [28]

Answer:

\mathbf{X_E (2) =  1}

\mathbf{X_E (-2) = 0 }  

\mathbf{\{ x \in Z: X_E(x) = 1\}  = E}

Step-by-step explanation:

Let E be the set of all even positive integers in the universe Z of integers,

i.e

E = {2,4,6,8,10 ....∞}

X_E : Z \to R be the characteristic function of E.

∴

X_E(x) = \left \{ {{1 \ if  \ x \ \  is \ an \ element \ of \ E} \atop {0 \ if  \ x \ \  is \ not \ an  \ element \ of \ E}} \right.

For XE(2)

\mathbf{X_E (2) =  1}  since x is an element of E (i.e the set of all even numbers)

For XE(-2)

\mathbf{X_E (-2) = 0 }   since  - 2 is less than 0 , and -2 is not an element of E

For { x ∈ Z: XE(x) = 1}

This can be read as:

x which is and element of Z such that X is also an element of x which is equal to 1.

∴

\{ x \in Z: X_E(x) = 1\} = \{ x \in Z | x \in E\} \\ \\  \mathbf{\{ x \in Z: X_E(x) = 1\}  = E}

E = {2,4,6,8,10 ....∞}

5 0
3 years ago
There are five different cards numbered 1 through 5. Assume the cards are randomly chosen. If the first card picked was a 2 and
alexandr402 [8]

Answer:

Step-by-step explanation:

3 0
3 years ago
4(x-12)^1/3 = -16<br> Help please, thank you
Lina20 [59]

Hello!

4 (x-12) ^ 1/3 = -16

Step 1. Simplify each side of the equation, 4/ 3x + −16 = −16 and 4 /3 x −16 = −16

Step 2. Add 16 to both sides, 4 /3 x − 16 + 16 = −16 + 16

Step 3: Multiply both sides by 3/4, ( 3/4)*(4/3x)=(3/4)*(0)

Final Answer: x= 0

Hope I could help! :)


7 0
3 years ago
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