All categories

3 years ago

4 times a number is increased by 15, the answer is the same as when 70 is decreased by the number

Mathematics

2 answers:

pentagon [3]3 years ago

3 0

4n+15=70+n

I'm pretty sure this is the answer

Have a good day!

galina1969 [7]3 years ago

3 0

4x +15 = 70 -x

if you want to solve it

add both sides by x and you will have

5x+15=70
minus both sides 15 and you will have
5x= 55

divide both sides by 5 and you will get

x=11

You might be interested in

I bought 1/2 gallon of paint then I found 1/3 of paint in my garage how much more paint do I need to have 3 gallons of paint

Ostrovityanka [42]

1/2 + 1/3 = (3*1)+(2*1) / (2*3) = (3+2)/6 = 5/6
tinha 5/6 de litro
para 1 litro faltam 4/6 de litro
para 3 litros faltam 2 litros e 4/6 de litro ou, simplificando:
4/6 = 2/3, logo, faltam 2 litros e 2/3 de litro.

6 0

3 years ago

Given f(x)=-8x+5 And g(x)=10x+2what is g(x) - f(x)

lidiya [134]

G(x)-f(x)=10x+2- (-8x+5)
=10x+2+8x-5
=18x-3

5 0

3 years ago

Write the first five terms of the sequence defined by the explicit formula

denis-greek [22]

<u>Answer:</u>

The correct answer option is: 19, 13, 3, -11, -29.

<u>Step-by-step explanation:</u>

We are given the following explicit formula for an arithmetic sequence:

$a_n=21-2n^2$

So to find the first five terms of this sequence, we will substitute the values of $n$ (num here in the given formula:

$a_1=21-2(1)^2\\\\a_1=19$

$a_2=21-2(2)^2\\\\a_2=13$

$a_3=21-2(3)^2\\\\a_3=3$

$a_4=21-2(4)^2\\\\a_4=-11$

$a_5=21-2(5)^2\\\\a_5=-29$

Therefore, the first five terms of the sequence defined by the explicit formula $a_n=21-2n^2$ are 19, 13, 3, -11, -29.

5 0

3 years ago

Read 2 more answers

A submersible traveling at a depth of 250 feet dives at an angle of 15 degrees with respect to a

kipiarov [429]

Answer:

$\boxed{\text{652 ft}}$

Step-by-step explanation:

The submersible is diving at a down angle of 15° along the hypotenuse AC of triangle ABC.

Its horizontal track along the surface AB is 1500 ft.

$\begin{array}{rcl}\tan A & = &\dfrac{BC}{AC}\\\\\tan 15^{\circ} & = & \dfrac{a}{1500}\\\\0.2679 & = & \dfrac{a}{1500}\\\\a & = & 1500 \times 0.2679\\& = & \textbf{402 ft}\\\end{array}$