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Vika [28.1K]
3 years ago
10

HELP ASAP ILL MARK BRAINLIEST

Mathematics
2 answers:
Archy [21]3 years ago
7 0
3. choosing two scoops of ice cream.
you can’t choose any of the rest, it’s all random except 3
Viefleur [7K]3 years ago
6 0

Answer:

the 3rd one. the rest are randomized.

Step-by-step explanation:

You might be interested in
A motorboat moves across a lake. It begins at 50km from shore after 9 minutes it is 14 km from shore. What’s it’s distance from
agasfer [191]

Answer:

List all of the solutions.

50 k m =

9 m i n u t e s =

14 k m =

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is the solution of equations graphed below?<br>A. (2,4)<br>B. (4,2)<br>C. (0,6)<br>D. (6,0)​
vivado [14]

Answer:

(4,2)

Step-by-step explanation:

The solution to the system is where the two graphs overlap

The two graphs cross at x=4 y =2

(4,2)

3 0
3 years ago
Read 2 more answers
Please please help me!!!! :)
kifflom [539]

Answer:

Measure of ∠5 is 142°

Step-by-step explanation:

We are given that, Lines L and M are parallel.

As, the third line is intersecting both line L and M.

<em>We know that, 'The opposite angles formed by the intersecting lines are equal'.</em>

Since, the sum of the four angles formed by the third line and M is 360°.

So, we get,

∠1 + ∠6 + ∠7 + 38 = 360°

i.e. 2∠1 + 2×38°  = 360°

i.e. 2∠1 = 360° - 76°

i.e. 2∠1 = 284°

i.e. ∠1 = 142°

Thus, ∠1 = ∠7 = 142°

Since, L and M are parallel.

So, ∠3 = ∠5 = 142°

Hence, we get that measure of ∠5 is 142°.

3 0
3 years ago
Plz help Ill give brainliest for first answer
faltersainse [42]

Answer:

ok ask the question plzzzzz

5 0
3 years ago
Read 2 more answers
Explain the special pattern for sketching a parabola
Lady bird [3.3K]

Answer:

the parabola can be written as:

f(x) = y = a*x^2 + b*x + c

first step.

find the vertex at:

x  = -b/2a

the vertex will be the point (-b/2a, f(-b/2a))

now, if a is positive, then the arms of the parabola go up, if a is negative, the arms of the parabola go down.

The next step is to see if we have real roots by using the Bhaskara's equation:

x =  \frac{-b +-\sqrt{b^2 -4ac} }{2a}

Now, draw the vertex, after that draw the values of the roots in the x-axis, and now conect the points with the general draw of the parabola.

If you do not have any real roots, you can feed into the parabola some different values of x around the vertex

for example at:

x =  (-b/2a) + 1 and x =  (-b/2a) - 1

those two values should give the same value of y, and now you can connect the vertex with those two points.

If you want a more exact drawing, you can add more points (like x =  (-b/2a) + 3 and x =  (-b/2a) - 3) and connect them, as more points you add, the best sketch you will have.

8 0
3 years ago
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