All categories

3 years ago

Ms. Lynch has 21 coins in nickels and dimes. Their total value is $1. 65. How many of each coin does she have? Please answer!!

Mathematics

2 answers:

jenyasd209 [6]3 years ago

5 0

Hi!

Ms. Lynch has 21 coins in nickels and dimes. Their total value is $1. 65. How many of each coin does she have?

12 x 0.1 = 1.2

9 x 0.05 = 0.45

1.2 + 0.45 = $1.65

Answer:

She has 12 Dimes and 9 Nickels!

timama [110]3 years ago

3 0

Hi, there

<u>Question:Ms. Lynch has 21 coins in nickels and dimes. Their total value is $1. 65. How many of each coin does she have?</u>

Explanation:

1.65 x 21

Answer 34.65

You might be interested in

Percent equations the question is blank % of 75 = 30

lubasha [3.4K]

Answer:

Step-by-step explanation:

30/75 = .4

4 0

3 years ago

Read 2 more answers

How would I solve; A bakery has 456 dozen cookies. How many individual cookies are there ?

Over [174]

Hi :")

Answer:

5472

Step-by-step explanation:

a dozen = 12 identical bodies

456 dozen cookies there are

12 x 456 = 5472

Good Luck ;)

#Turkey

6 0

3 years ago

Read 2 more answers

Which statement is true about the speeds of the two cars

galben [10]

What two cars, I don’t see anything

6 0

2 years ago

Use the exponential decay model, Upper A equals Upper A 0 e Superscript kt, to solve the following. The half-life of a certai

Akimi4 [234]

Answer:

It will take 7 years ( approx )

Step-by-step explanation:

Given equation that shows the amount of the substance after t years,

$A=A_0 e^{kt}$

Where,

$A_0$ = Initial amount of the substance,

If the half life of the substance is 19 years,

Then if t = 19, amount of the substance = $\frac{A_0}{2}$ ,

i.e.

$\frac{A_0}{2}=A_0 e^{19k}$

$\frac{1}{2} = e^{19k}$

$0.5 = e^{19k}$

Taking ln both sides,

$\ln(0.5) = \ln(e^{19k})$

$\ln(0.5) = 19k$

$\implies k = \frac{\ln(0.5)}{19}\approx -0.03648$

Now, if the substance to decay to 78% of its original amount,

Then $A=78\% \text{ of }A_0 =\frac{78A_0}{100}=0.78 A_0$

$0.78 A_0=A_0 e^{-0.03648t}$

$0.78 = e^{-0.03648t}$

Again taking ln both sides,

$\ln(0.78) = -0.03648t$

$-0.24846=-0.03648t$

$\implies t = \frac{0.24846}{0.03648}=6.81085\approx 7$

Hence, approximately the substance would be 78% of its initial value after 7 years.

5 0

2 years ago

The functions f(x) and g(x) in the graph below are most likely which two equations?

gtnhenbr [62]

Answer:

It's C.

Step-by-step explanation:

The red curve pass through the point (0, 1) and also y = 2 when x = 1 , so this is y = 2^x. The inverse is the reflection of f(x) in x = y so the blue curve is y = log2 x.

6 0

3 years ago