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inysia [295]
2 years ago
8

A bicycle rental is 15 plus 9.50 per hour. An electric scooter rental is 25 plus 7 per hour. How many hours would you need to re

nt the bike for the price to be equal to the scooter for the same amount of time? Record your answer and fill in the bubbles on your answer document. Be sure to use the correct place value.
Mathematics
1 answer:
Setler79 [48]2 years ago
4 0

Answer:

4 hours

Step-by-step explanation:

Hour1-

Bicycle = 24.50

ElectricScooter = 32

Hour2-

Bicycle = 34

ElectricScooter = 39

Hour3-

Bicycle = 43.5

ElectricScooter = 46

Hour4 -

Bicycle = 53

ElectricScooter = 53

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Answer:

(5, 11) and (2, 2)

Step-by-step explanation:

y = (x-2)² + 2

y + 4 = 3x

(x-2)² + 2 + 4 = 3x

x² - 4x + 4 + 6 = 3x

x² - 7x + 10 = 0

(x - 5)(x - 2) = 0

x - 5 = 0, x = 5

x - 2 = 0, x = 2

y = (5-2)² + 2 = 11

(5, 11)

y = (2-2)² + 2 = 2

(2, 2)

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4 years ago
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Nutka1998 [239]
I think the answer is -2

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Hope this helps!
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What the answer now to the question
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Step-by-step explanation:

<em>Hello</em><em>!</em><em>!</em><em>!</em>

<em>Given</em><em>, </em><em> </em><em>VXW</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>Right angled triangle</em><em> </em><em>where</em><em> </em><em>WV</em><em> </em><em>=</em><em>4</em><em> </em><em>and</em><em> </em><em>XV</em><em> </em><em>=</em><em>5</em><em>.</em>

<em>now</em><em>,</em><em> </em><em>b</em><em>y</em><em> </em><em>taking</em><em> </em><em>reference angle</em><em> </em><em>as angle </em><em>W</em><em>,</em><em> </em><em>and</em><em> </em><em>using</em><em> </em><em>tangent</em><em> </em><em>we</em><em> </em><em>get</em><em>;</em>

<em>p</em><em>=</em><em>5</em>

<em>b</em><em>=</em><em>4</em>

<em>again</em><em>, </em>

<em>tan</em><em> </em><em>thita</em><em> </em><em>=</em><em>p</em><em>/</em><em>b</em>

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<em>so</em><em>,</em><em> </em><em>tan</em><em> </em><em>thita</em><em> </em><em>=</em><em>1</em><em>.</em><em>2</em><em>5</em><em>.</em>

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<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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