Question

Starting at home, Omar traveled uphill to the gift store for 30 minutes at just 10 mph. He then traveled back home along the same path downhill at a speed of 30 mph. What is his average speed for the entire trip from home to the gift store and back?

Answer 1

Single journey = 0.5*10 = 5 miles 
goung back time = 5 / 30 = 1/6 of an hour

average
speed foe whole journey  = 10 / (1/2 + 1/6) = 10 * 3 / 2 = 15 mph

Answer 2

Answer:

The average speed of Omar for the entire trip from home to the gift store and back is 15 mph.

Step-by-step explanation:

It is given that Omar traveled uphill to the gift store for 30 minutes at just 10 mph.

1 hour = 60 minutes

0.5 hours  = 30 minutes

Total distance between home to gift store is

$Distance=0.5\times 10=5$

The distance between home to gift store is 5 miles.

Time taken by Omar along the same path downhill at a speed of 30 mph is

$\frac{5}{30}=\frac{1}{6}hours$

Total distance of the entire trip from home to the gift store and back is

$2\times 5=10miles$

Formula for average speed is

$Speed=\frac{\text{Total distance}}{\text{Total time}}$

$Speed=\frac{10}{0.5+\frac{1}{6}}$

$Speed=\frac{10}{\frac{4}{6}}$

$Speed=15$

Therefore the average speed of Omar for the entire trip from home to the gift store and back is 15 mph.