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2 years ago

How do I factor this? Please explain the steps

Mathematics

1 answer:

Elena-2011 [213]2 years ago

7 0

Answer: 2(x^2+1)^3 (-8x^4-16x^2+x-8)

Step-by-step explanation:

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(-7x3 + 5ax - 3) + (7x3 + 5 - 9ax)

Semmy [17]

Answer:

-7x^3 + 5ax - 3 + 7x^3 + 5 - 9ax

-4ax + 2

answer is c

Step-by-step explanation:

5 0

3 years ago

Do supplementary angles form right angles? yes or no

Anuta_ua [19.1K]

Answer:

Yes i

Step-by-step explanation:

A supplementary angle can be two angles that sum up to 180 if you want you can have 2 angles that are 90 degrees that add up to 180 so therefore that would make a right angle.

6 0

3 years ago

Write a x (-a)x 13 x a x (-a) x 13 in power notation

miss Akunina [59]

Answer:

$a\times (-a)\times 13\times a\times (-a)\times 13$ can be written in power notation as $a^{4}\times 13^{2}$

Step-by-step explanation:

The given expression

$a\times (-a)\times 13\times a\times (-a)\times 13$

Writing a\times (-a)\times 13\times a\times (-a)\times 13 in power notation:

Let

$a\times (-a)\times 13\times a\times (-a)\times 13$

= $[13\times13][(a\times (-a)\times a\times (-a)]$

$13\times13 = 13^{2}$ , $a\times a = a^{2}$ , $(-a)\times (-a) = (-a)^{2}$

So,

$=[13^{2}][a^2\times (-a)^2]$

$(-a)^2 = a^{2}$

So,

$=[13^{2}][a^2\times a^2]$

As ∵ $a^{m} \times a^{n}=a^{m+n}$

$=[13^{2}][a^{2+2}]$

As ∵ $a^{m} \times a^{n}=a^{m+n}$

$=13^{2}\times a^{4}$

$=a^{4}\times 13^{2}$

Therefore, $a\times (-a)\times 13\times a\times (-a)\times 13$ can be written in power notation as $a^{4}\times 13^{2}$

Keywords: power notation

Learn more about power notation from brainly.com/question/2147364

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5 0

2 years ago

Factor out 1/4 out of 1/4x+11/4

cluponka [151]

$\frac{1}{4} x+\frac{11}{4}$

we can rewrite it as

$\frac{1}{4}* x+\frac{1}{4}*11$

we can see that 1/4 is in multiple in both terms

so, we can factor it out

so, we get

$\frac{1}{4}( x+11)$ ..............Answer

5 0

3 years ago

Given the system of equations:

uranmaximum [27]

Answer:

x=4

y=2

Step-by-step explanation:

2x+2y=12

x−y=2

In order to solve by elimination, coefficients of one of the variables must be the same in both equations so that the variable will cancel out when one equation is subtracted from the other.

2x+2y=12,x−y=2

To make 2x and x equal, multiply all terms on each side of the first equation by 1 and all terms on each side of the second by 2.

2x+2y=12,2x+2(−1)y=2×2

Simplify.

2x+2y=12,2x−2y=4

Subtract 2x−2y=4 from 2x+2y=12 by subtracting like terms on each side of the equal sign.

2x−2x+2y+2y=12−4

Add 2x to −2x. Terms 2x and −2x cancel out, leaving an equation with only one variable that can be solved.

2y+2y=12−4

Add 2y to 2y.

4y=12−4

Add 12 to −4.

4y=8

Divide both sides by 4.

y=2

Substitute 2 for y in x−y=2. Because the resulting equation contains only one variable, you can solve for x directly.

x−2=2

Add 2 to both sides of the equation.

x=4

The system is now solved.

x=4,y=2

Correct choice is B) x=4.

8 0

2 years ago

Read 2 more answers