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3 years ago

A carton of juice contains 64 ounces Miss Wilson bought six cartons of juice how many ounces of juice did she buy

Mathematics

2 answers:

larisa [96]3 years ago

7 0

Answer:

384

Step-by-step explanation:

1 carton= 64 ounces

6 cartons=64x6=384

Oduvanchick [21]3 years ago

3 0

Answer:

384 ounces

Step-by-step explanation:

1 carton=64 oz

6 cartons=64×6=384

You might be interested in

The prime factorization of 441 is

OLga [1]

441 is odd, so we can't divide it by 2.

Since the sum of its digits is $4+4+1=9$ , which is divisible by 3, we can divide 441 by 3, and we have

$441\div 3=147$

Which is still divisible by 3, because $1+4+7=12$ . We have

$147\div 3=49$

49 is not divisible by 3 anymore, nor by 5 (it doesn't end with 0 or 5).

It is divisible by 7 though, we have

$49\div 7=7$

and finally,

$7\div 7=1$

So, the factorization of 441 is

$441=3^2\times 7^2$

8 0

2 years ago

Read 2 more answers

There are 36 bikes in a store (18 pairs). 1 pair(s) are yellow, 3 pairs are red, and the rest are purple. If you took out a purp

LenaWriter [7]

Answer: 27/36

Step-by-step explanation: It says there are 36 bikes (18 pairs), meaning that there are 2 bikes per pair because 18 multiplied by 2 is 36.

1 pair (2 bikes) are yellow.

3 pairs (6 bikes) are red.

For purple, add yellow and red together: 2 + 6 = 8. Subtract the total number of bikes from this: 36 - 8 = 28 purple bikes.

If you take out 1 purple bike, this leaves you with 27. The probability of choosing a purple bike out of the total (36), is 27/36.

Please let me know if this is correct or wrong.

8 0

2 years ago

Find the area of the region which is inside the polar curve r=5sin(θ) but outside r=4. Round your answer to four decimal places

natka813 [3]

The area of the region which is inside the polar curve r = 5 sinθ but outside r = 4 will be 3.75 square units.

<h3>What is an area bounded by the curve?</h3>

When the two curves intersect then they bound the region is known as the area bounded by the curve.

The area of the region which is inside the polar curve r = 5 sinθ but outside r = 4 will be

Then the intersection point will be given as

$\rm 5 \sin \theta = 4\\\\\theta = 0.927 , 2.214$

Then by the integration, we have

$\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214}[ (5 \sin \theta)^2 - 4^2] d\theta \\\\\\\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214} [25\sin ^2 \theta - 16] d\theta \\\\\\\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214} [ \dfrac{25}{2}(1 - \cos 2\theta ) - 16] d\theta \\$

$\rightarrow \dfrac{1}{2} [\dfrac{25 \theta }{5} - \dfrac{25 \cos 2\theta }{2} - 16\theta]_{0.927}^{2.214} \\\\\\\rightarrow \dfrac{1}{2} [\dfrac{25(2.214 - 0.927) }{5} - \dfrac{25 (\cos 2\times 2.214 - \cos 2\times 0.927) }{2} - 16(2.214 - 0.927]\\$