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Each step of the proof are:
- a || b
- ∠1 ≅ ∠5
- ∠1 ≅ ∠5
- ∠5 ≅ ∠7
- ∠5 ≅ ∠7
- ∠1 ≅ ∠7
- ∠1 ≅ ∠7
<h3>How to complete the proof?</h3>
The given parameter is:
Lines a and b are parallel.
This is represented as; a || b
Corresponding angles are equal.
∠1 and ∠5 are corresponding angles.
So, we have: ∠1 ≅ ∠5
Also, they are congruent.
So, we have ∠1 ≅ ∠5
Vertical angles are equal.
∠5 and ∠7 are vertical angles.
So, we have: ∠5 ≅ ∠7
Also, they are congruent.
So, we have ∠5 ≅ ∠7
According to the transitive property;
If ∠1 ≅ ∠5 and ∠5 ≅ ∠7, then ∠1 ≅ ∠7
Hence, it has been proved that ∠1 ≅ ∠7
Read more about congruent angles at:
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Answer:
+ C
This is my first time doing a double integral, so im only 90% sure in my answer
Step-by-step explanation:
You pretty much want to take the double integral of sinx + cosx
The anti-derivative of sinx = -cosx
The anti-derivative of cosx = sinx
So f' = -cosx + sinx
Now lets take the integral of f':
The anti-derivative of -cosx = sinx
The anti-derivative of sinx = -cosx
So, f(x) = sinx - cosx