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Mice21 [21]
2 years ago
13

Factor the trinomial x^2- 5x- 36 Which of the following is one of the factors?

Mathematics
2 answers:
JulijaS [17]2 years ago
5 0

Answer:

Final factor is (x-9)(x+4)

Step-by-step explanation:

Given expression is x^2- 5x- 36.

Now we need to factor that expression

x^2- 5x- 36

Find two numbers whose product is -36 and sum is -5.

Two such numbers oare -9 and +4. So we get:

=x^2- 9x+4x- 36

=x(x-9)+4(x-9)

=(x-9)(x+4)

Hence final factor is (x-9)(x+4)

bekas [8.4K]2 years ago
3 0

Answer:

(x-9) (x+4)

Step-by-step explanation:

x^2- 5x- 36

What two numbers multiply to -36 and add to -5

-9*4 = -36

-9+4 = -5

(x-9) (x+4)

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Of the 800 people at the concert, 42% of them are teenagers. How many teenagers are at the concert?
vovikov84 [41]

Answer:

There are 336 teenagers in the concert. Please Mark me brainliest if I am correct thank you and have a nice day.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Part A: Determine if the expression is one of our special products. If so, identify it by its general form:
kondaur [170]

Answer:

1.

Part A: Yes, it is (a - b)².

Part B: a² - 2ab + b² => (x - 6)² = x² - 12x + 36.

Part C: x² - 12x + 36.

2.

Part A: Not a special product.

Part B: Binomial distribution => (x + 8)(x + 1) = x² + 9x + 8.

Part C: x² + 9x + 8.

3.

Part A: Yes, it is (a + b)²

Part B: a² + 2ab + b² => (3x + 2)² = 9x² + 12x + 4.

Part C: 9x² + 12x + 4.

4.

Part A: Yes, it is (a + b)(a - b), a difference of squares.

Part B: a² - b² => 4x² - 49

Part C: 4x² - 49

5.

Part A: Not a special product.

Part B: Binomial distribution => (x - 5)(2x - 5) = 2x² - 15x + 25.

Part C: 2x² - 15x + 25

6 0
3 years ago
Reduce the ratio 8/12 to the lowest terms
Tanya [424]
The answer is 2/3
I hope this works for you :)
5 0
3 years ago
Find the domain and range of the function f(x)= 8|x|+sinx
erik [133]
Dominio:
(−∞,∞),{x|x∈R}

Rango:
(−∞,∞),{y|y∈R}
6 0
2 years ago
A can in the shape of a right cylinder is filled with 10W-40 oil. The weight of 10W-40 oil is 0.857 gram per cubic centimeter. I
Leya [2.2K]
To solve this, we have to find the volume of the cylinder first.  The formula to be used is V =  \pi  r^{2} h

Given:V= ?r= 6cmh= 10cm
Solution:V =  \pi  r^{2} h
V= (3.14)(6cm)^{2} x 10cmV= (3.14)(36cm^{2}) x 10cmV= (113.04cm^{2}) x 10cmV= 1130.4cm^3
Finding the volume of the cylinder, we can now solve what the weight of the oil is.  Using the formula of density, Density = mass/volume, we can derive a formula to get the weight.
Given:Density = 0.857 gm/cm^3Volume = 1130.4 cm^3
Solution:weight = density x volumew= (0.857 gm/cm^3) (1130.4cm^3)w= 968.7528 gm
The weight of the oil is 968.75 gm.
5 0
2 years ago
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