Question

Help Please..............​

Answer 1

Answer:

$9\frac{3}{2}$ smallest

$27\frac{1}{3}$

$125\frac{2}{3}$ largest

Step-by-step explanation:

First change the mixed numbers into an improper fractions.

$9\frac{3}{2}$ = $\frac{21}{2}$  9 x 2 = 18 + 3 = 21

$27\frac{1}{3}$ = $\frac{82}{3}$ 27 x 3 = 81 + 1 = 82

$125\frac{2}{3}$ = $\frac{377}{3}$ 125 x 3 = 375 + 2 = 377

Find the least common denominator.

2 and 3 have 6

$\frac{21}{2}$ = $\frac{63}{6}$ smallest

$\frac{82}{3}$ = $\frac{164}{6}$ medium

$\frac{377}{3}$ = $\frac{754}{6}$ largest