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3 years ago

The line that is the perpendicular bisector of the segment whose endpoints are R(-1, 6) and S(5, 5)

2 answers:

8 0

I think what you are looking for is to indicate an ecuation for this. So lets do the procedure:
First you need to find the slope of this line.
<span>(5 - 6)/(5 + 1) = -1/6 </span>
<span>So, The slope of the perpendicular line is the opposite reciprocal, which is </span>
<span>+6/1.</span><span>Now we know the slope of the line but still have to find the mid point of the line. </span>
That is why we are going to <span>use the mid point equation </span>
<span>x = (-1 + 5)/2 = 2 </span>
<span>y = (6 + 5)/2 = 11/2 </span><span> </span>
<span>(y - 11/2) = 6(x - 2) </span>
<span>The last thing you do is rearrange the equation to get y = 6x - 6.5
Hope this is what you were looking for </span>

KengaRu [80]3 years ago

3 0

Answer:

On odyssey ware it's 12x-2y=13

Step-by-step explanation:

yup

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Consider an m-by-n chessboard with m and n both odd. To fix the notation, suppose that the square in the upper left-hand corner

beks73 [17]

There are two cases to consider.

A) The removed square is in an odd-numbered column (and row). In this case, the board is divided by that column and row into parts with an even number of columns, which can always be tiled by dominos, and the column the square is in, which has an even number of remaining squares that can also be tiled by dominos.

B) The removed square is in an even-numbered column (and row). In this case, the top row to the left of that column (including that column) can be tiled by dominos, as can the bottom row to the right of that column (including that column). The remaining untiled sections of the board have even numbers of rows, so can be tiled by dominos.

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Perhaps the shorter answer is that in an odd-sized board, the corner squares are the ones that there is one of in excess. Cutting out one that is of that color leaves an even number of squares, and equal numbers of each color. Such a board seems like it <em>ought</em> to be able to be tiled by dominos, but the above shows there is actually an algorithm for doing so.

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3 years ago

A family of 10 purchased tickets to the county fair. Tickets for adults cost $6 and tickets for children cost $3. If the total c

blsea [12.9K]

Answer:

3 adults 2 children

Step-by-step explanation:

(3 x 10) + (2 x 6)

30+12=42

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3 years ago

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General Mills, the manufacturer of Lucky Charms, claims that their new boxes hold 25% more cereal. If their original box held 50

shutvik [7]

Answer:

625

Step-by-step explanation:

basically, half of 500 is 250 halve that you get a quater of 500 (25%)

500+125=625

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3 years ago

What is the equation of the line that has a slope of 0 and passes through the point (6,-8)

Fofino [41]

$\bf (\stackrel{x_1}{6}~,~\stackrel{y_1}{-8})~\hspace{10em} slope = 0 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-8)=0(x-6)\implies y+8=0\implies y=-8$

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3 years ago

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Unit 7 polygons & quadrilaterals homework 3: rectangles Gina Wilson answer key

Irina-Kira [14]

Answer:

In the image attached you can find the Unit 7 homework.

We need to findt he missing measures of each figure.

Notice that the first figure is a rectangle, which means opposite sides are congruent so,

VY = 19

WX = 19

YX = 31

VW = 31

To find the diagonals we need to use Pythagorean's Theorem, where the diagonals are hypothenuses.

$VX^{2}=19^{2}+31^{2}\\ VX=\sqrt{361+961}=\sqrt{1322} \\VX \approx 36.36$

Also, $YW \approx 36.36$ , beacuse rectangles have congruent diagonals, which intercect equally.

That means, $ZX = \frac{VX}{2} \approx \frac{36.36}{2}\approx 18.18$

Figure number two is also a rectangle.

If GH = 14, that means diagonal GE = 28, because diagonals intersect in equal parts.

Now, GF = 11, because rectangles have opposite sides congruent.

DF = 28, because in a reactangle, diagonals are congruent.

HF = 14, because its half of a diagonal.

To find side DG, we need to use Pythagorean's Theorem, where GE is hypothenuse

$GE ^{2}=11^{2}+DG^{2}\\28^{2}-11^{2}=DG^{2}\\DG=\sqrt{784-121}=\sqrt{663}\\ DG \approx 25.75$

This figure is also a rectangle, which means all four interior angles are right, that is, equal to 90°, which means angle 11 and the 59° angle are complementary, so

$\angle 11 +59\°=90\°\\\angle 11=90\°-59\°\\\angle 11=31\°$

Now, angles 11 and 4 are alternate interior angles which are congruent, because a rectangle has opposite congruent and parallel sides.

$\angle 4 = 31\°$

Which means $\angle 3 = 59\°$ , beacuse it's the complement for angle 4.

Now, $\angle 6 = 59\°$ , because it's a base angle of a isosceles triangle. Remember that in a rectangle, diagonals are congruent, and they intersect equally, which creates isosceles triangles.