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3 years ago

The line that is the perpendicular bisector of the segment whose endpoints are R(-1, 6) and S(5, 5)

2 answers:

8 0

I think what you are looking for is to indicate an ecuation for this. So lets do the procedure:
First you need to find the slope of this line.
(5 - 6)/(5 + 1) = -1/6 
So, The slope of the perpendicular line is the opposite reciprocal, which is 
+6/1.Now we know the slope of the line but still have to find the mid point of the line. 
That is why we are going to use the mid point equation 
x = (-1 + 5)/2 = 2 
y = (6 + 5)/2 = 11/2 
(y - 11/2) = 6(x - 2) 
The last thing you do is rearrange the equation to get y = 6x - 6.5
Hope this is what you were looking for

KengaRu [80]3 years ago

3 0

Answer:

On odyssey ware it's 12x-2y=13

Step-by-step explanation:

yup

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Express this to single logarithm

zzz [600]

Answer: $\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right)$

We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.

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Explanation:

It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.

I'm going to use these three log rules, which apply to any base.

log(A) + log(B) = log(A*B)
log(A) - log(B) = log(A/B)
B*log(A) = log(A^B)

From there, we can then say the following:

$\frac{1}{2}\log_{2}\left(m\right)-3\log_{2}\left(n\right)+2\log_{2}\left(q\right)\\\\\log_{2}\left(m^{1/2}\right)-\log_{2}\left(n^3\right)+\log_{2}\left(q^2\right) \ \text{ .... use log rule 3}\\\\\log_{2}\left(\sqrt{m}\right)+\log_{2}\left(q^2\right)-\log_{2}\left(n^3\right)\\\\\log_{2}\left(\sqrt{m}*q^2\right)-\log_{2}\left(n^3\right) \ \text{ .... use log rule 1}\\\\\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right) \ \text{ .... use log rule 2}$

8 0

3 years ago

Please answer #1 for me only ! What is my Y for #1 , don't forget to graph !

mart [117]

The table and the graph is shown in the following picture

7 0

3 years ago

HURYY PLEASE EXPLAIN ASAP!!!

Wittaler [7]

Answer:

The answer is 527.5km^3 .

Step-by-step explanation:

The formula for cylinders is πr2h. (pie times twice the height)

3.14(12)(2)(7) = 527.52

5 0

3 years ago

Read 2 more answers

The amount of money spent on textbooks per year for students is approximately normal.

Ostrovityanka [42]

Answer:a

$336.04 < \mu < 443.96$

The margin of error will increase

The margin of error will decreases

The 99% confidence interval is $0.4107 < p < 0.4293$

Step-by-step explanation:

From the question we are told that

The sample size $n = 19$

The sample mean is $\= x = \$\ 390$

The standard deviation is $\sigma = \$ \ 120$

Given that the confidence level is 95% then the level of significance is mathematically represented as

$\alpha = 100 - 95$

$\alpha = 5 \%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table

$Z_{\frac{\alpha }{2} } = 1.96$

The margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma}{\sqrt{n} }$

=> $E = 1.96 * \frac{120}{\sqrt{19} }$

=> $E = 53.96$

The 95% confidence interval is

$\= x - E < \mu < \= x + E$

=> $390 - 53.96 < \mu < 390 - 53.96$

=> $336.04 < \mu < 443.96$

When the confidence level increases the $Z_{\frac{\alpha }{2} }$ also increases which increases the margin of error hence the confidence level becomes wider