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kap26 [50]
3 years ago
10

What is the graph of y-(-3)=-1/2(x-(0))?

Mathematics
1 answer:
erik [133]3 years ago
3 0
Y - (-3) = -1/2(x - (0))
y + 3 = -1/2 x
y = -1/2 x - 3

The graph of the function is a straight line with a slope of -1/2.
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Para iniciar un negocio, una pareja pide $5.500.000 para comprar equipo y suministros. Si el préstamo tiene una tasa de 14% de i
Sunny_sXe [5.5K]

Answer:

They will have to pay $5,692,500 in 90 days.

Deben pagar $5,692,500 pagar al final de un período de 90 días.

Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

E = P*I*t

In which E are the earnings, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time, in years..

After t years, the total amount of money is:

T = E + P.

In this question:

P = 5500000, I = 0.14

3 months is 3/12 = 1/4 = 0.25 of an year. So t = 0.25

Then the interest accrued is:

E = P*I*t = 5500000*0.14*0.25 = 192500

What they will have to pay:

T = 192500 + 5500000 = 5692500

They will have to pay $5,692,500 in 90 days.

Deben pagar $5,692,500 pagar al final de un período de 90 días.

7 0
3 years ago
Given f(x) = 6x + 2, find f(x-3)
Molodets [167]

Answer:

6x -16

Step-by-step explanation:

f(x) = 6x + 2

f(x-3) =

Replace x with x-3

f(x) = 6(x-3) + 2

   Distribute

    = 6x - 18 +2

    = 6x -16

6 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST. Billy ordered a pizza with a crust that is 10π inches long. What is the area of the pizza?
Allisa [31]

Answer:

~31.42

Step-by-step explanation:

I multiplied 10 x pi and it gave me 31.4159265359 and I rounded up to 31.42

3 0
3 years ago
11. Kamala borrowed 26400 from a bank to buy a scooter at a rate of 15% per annum compounded yearly. What amount will she pay at
oee [108]
<h2>Answer </h2>

Amount (A) = P[1 + (r/100)]n

Principal (P) = ₹ 26400

Time period (n) = 2 years 4 months

Rate % (R) = 15% compounded annually

<h3>Steps </h3>

First, we will calculate Compound Interest (C.I) for the period of 2 years

A = P[1 + (r/100)]n

= 26400[1 + (15/100)]²

= 26400[(100/100) + (15/100)]²

= 26400 × 115/100 × 115/100

= 26400 × 23/20 × 23/20

= 26400 × 1.3225

= 34914

C.I. = A - P

= 34914 - 26400

= 8514

Now, we will find Simple Interest (S.I) for the period of 4 months

Principal for 4 months after C.I. for 2 years = ₹ 34,914

<h3>We know that ,</h3>

S.I = PRT/100

Here T = 4 months = 4/12 years = 1/3 years

S.I. for 4 months = (1/3) × 34914 × (15/100)

= (1/3) × 34914 × (3/20)

= 34914/20

= 1745.70

Total interest for 2 years 4 months = 8514 + 1745.70

= 10259.70

Total amount for 2 years 4 months = 26400 + 10259.70

= ₹ 36659.70

<h3>So , the correct answer is ₹ 36659.70 . </h3>

6 0
2 years ago
Read 2 more answers
Find the length of arc JK. <br> (Round to the nearest hundredth).
Naddika [18.5K]

Answer:

Step-by-step explanation:“My head was pounding. It was like my insides had swollen so much they were pushing on my skull.”

5 0
3 years ago
Read 2 more answers
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