Answer:
No not correct
Step-by-step explanation:
We are given information that Maya came to know that 0.63 pf Pal school is female and 0.47 of Elm school is female.
Without knowing the total number of students in each school, we cannot conclude that 0.63 is greater than 0.47
For example, say number of students in Oak school be 100, and in Elm school be 200
Females in Oak school = 0.63(100) =63
Females in Elm school = 0.47(200) = 94
We find that there are more females in Elm school
So with the information given, we cannot conclude she is correct , there are chances for her being wrong also.
Awnser is c I just did this
Answer:
The value of the snack bar is $ 2 and that of the magazine subscription is 25 $
Step-by-step explanation:
We have a system of two equations and two unknowns, which would be the following:
let "x" be the cost of the snack bar
Let "y" be the cost of the magazine subscription
16 * x + 4 * y = 132
20 * x + 6 * y = 190 => y = (190 - 20 * x) / 6
replacing:
16 * x + 4 * (190 - 20 * x) / 6 = 132
16 * x + 126.66 - 13.33 * x = 132
2.66 * x = 132 - 126.66
x = 5.34 / 2.66
x = 2
for "y":
y = (190 - 20 * 2) / 6
y = 25
Which means that the value of the snack bar is $ 2 and that of the magazine subscription is 25 $
You didn’t even post a diagram
which of the following diagram represent a relation that is not a function
