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kogti [31]
2 years ago
10

Can someone please help me with question c? Would be really appreciated :) (Picture is attached)

Mathematics
2 answers:
Romashka [77]2 years ago
8 0

Answer:

approx. 1,680,185

Step-by-step explanation:

Out of the 6,547,000 people who they surveyed in 1998, 6.5% of the Canadians(combining the 1.9 and 4.6 percent of males and females who voted for basketball) chose basketball. Assuming the same percentage of people favors basketball in 2004, then you'd simply need to find 6.5% of the population of 2004(which, as given, is 25,849,000), and 1,680,185 is 6.5% of the population.

vodka [1.7K]2 years ago
6 0

Answer: 1,680,000

Step-by-step explanation:

Assumptions: The percentage would still be that same from 1994 to 2004

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Can anyone help me please? I have no idea what to do! :'(
liberstina [14]

Answer:

7) 10^(3/2)

8) 2^(1/6)

9) 2^(5/4)

10) 5^(5/4)

Step-by-step explanation:

7)  (√10)^3 = 10^(3/2)

8)  6 root 2 = 2^(1/6)

9)  (4 root 2)^5 = 2^(5/4)

10) (4 root 5)^5 = 5^(5/4)

5 0
2 years ago
Solve the Inequality: m+16>8m+2​
Setler [38]

Answer:

m<2

Step-by-step explanation:

To get to this, you first need to move the variable to one side, so you could subtract m from both sides to make the equation 16>7m+2. Next, you subtract 2 from both sides to make the equation into 14>7m. Finally, you would divide 7 from both sides to get 2>m, or m<2.

Hope this helps!

5 0
3 years ago
Describe the solution(s) to 9x² - 36x + 36 = 0 by just determining the radicand. Show your work. (10 points) Part B: Describe th
Mariana [72]

The solution to the equations are:

  • 9x² - 36x + 36 = 0 has two equal real solutions
  • x² - x + 4 = 0 has no real solutions
  • The factored expression of 4x² + 23 – 35 is 4(x² -3)

<h3>Part A: Describe the solution</h3>

The equation is given as:

9x\² - 36x + 36 = 0

The above equation is a quadratic equation which can be represented as:

ax\² + bx + c = 0

The discriminant (d) is calculated as:

d = b\² - 4ac

So, we have:

d = (-36)\² - 4 * 9 * 36

d = 0

A discriminant of 0 means that the equation has two equal real solutions

Hence, 9x² - 36x + 36 = 0 has two equal real solutions

<h3>Part B: Describe the solution</h3>

The equation is given as:

x\² - x + 4 = 0

The above equation can be represented as:

ax\² + bx + c = 0

The discriminant (d) is calculated as:

d = b\² - 4ac

So, we have:

d = (-1)\² - 4 * 1 * 4

d = -15

A discriminant of -15 means that the equation has no real solutions

Hence, x² - x + 4 = 0 has no real solutions

<h3>Part C: The solution to the expression</h3>

We have:

4x\² + 23 - 35

Evaluate the difference

4x\² -12

Factor out 4

4(x\² -3)

Hence, the factored expression of 4x² + 23 – 35 is 4(x² -3)

Read more about quadratic expressions at:

brainly.com/question/10449635

#SPJ1

5 0
1 year ago
United Airlines' flights from Denver to Seattle are on time 50 % of the time. Suppose 9 flights are randomly selected, and the n
Ivanshal [37]

Answer:

<u><em>a) The probability that exactly 4 flights are on time is equal to 0.0313</em></u>

<u><em></em></u>

<u><em>b) The probability that at most 3 flights are on time is equal to 0.0293</em></u>

<u><em></em></u>

<u><em>c) The probability that at least 8 flights are on time is equal to 0.00586</em></u>

Step-by-step explanation:

The question posted is incomplete. This is the complete question:

<em>United Airlines' flights from Denver to Seattle are on time 50 % of the time. Suppose 9 flights are randomly selected, and the number on-time flights is recorded. Round answers to 3 significant figures. </em>

<em>a) The probability that exactly 4 flights are on time is = </em>

<em>b) The probability that at most 3 flights are on time is = </em>

<em>c)The probability that at least 8 flights are on time is =</em>

<h2>Solution to the problem</h2>

<u><em>a) Probability that exactly 4 flights are on time</em></u>

Since there are two possible outcomes, being on time or not being on time, whose probabilities do not change, this is a binomial experiment.

The probability of success (being on time) is p = 0.5.

The probability of fail (note being on time) is q = 1 -p = 1 - 0.5 = 0.5.

You need to find the probability of exactly 4 success on 9 trials: X = 4, n = 9.

The general equation to find the probability of x success in n trials is:

           P(X=x)=_nC_x\cdot p^x\cdot (1-p)^{(n-x)}

Where _nC_x is the number of different combinations of x success in n trials.

            _nC_x=\frac{x!}{n!(n-x)!}

Hence,

            P(X=4)=_9C_4\cdot (0.5)^4\cdot (0.5)^{5}

                                _9C_4=\frac{4!}{9!(9-4)!}=126

            P(X=4)=126\cdot (0.5)^4\cdot (0.5)^{5}=0.03125

<em><u>b) Probability that at most 3 flights are on time</u></em>

The probability that at most 3 flights are on time is equal to the probabiity that exactly 0 or exactly 1 or exactly 2 or exactly 3 are on time:

         P(X\leq 3)=P(X=0)+P(X=1)+P(X=2)+P(X=3)

P(X=0)=(0.5)^9=0.00195313 . . . (the probability that all are not on time)

P(X=1)=_9C_1(0.5)^1(0.5)^8=9(0.5)^1(0.5)^8=0.00390625

P(X=2)=_9C_2(0.5)^2(0.5)^7=36(0.5)^2(0.5)^7=0.0078125

P(X=3)= _9C_3(0.5)^3(0.5)^6=84(0.5)^3(0.5)^6=0.015625

P(X\leq 3)=0.00195313+0.00390625+0.0078125+0.015625=0.02929688\\\\  P(X\leq 3) \approx 0.0293

<em><u>c) Probability that at least 8 flights are on time </u></em>

That at least 8 flights are on time is the same that at most 1 is not on time.

That is, 1 or 0 flights are not on time.

Then, it is easier to change the successful event to not being on time, so I will change the name of the variable to Y.

          P(Y=0)=_0C_9(0.5)^0(0.5)^9=0.00195313\\ \\ P(Y=1)=_1C_9(0.5)^1(0.5)^8=0.0039065\\ \\ P(Y=0)+P(Y=1)=0.00585938\approx 0.00586

6 0
3 years ago
Use quadratic regression to find
emmasim [6.3K]
Y= 4x^2 + 19x - 5 :)!
3 0
2 years ago
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