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amid [387]
3 years ago
15

The functions f(x) = (x + 5)^2 + 2 and g(x) = -(x − 3)^2−3 have been rewritten using the completing-the-square method. Is the ve

rtex for each function a minimum or a maximum? Explain your reasoning for each function.
Mathematics
1 answer:
Stolb23 [73]3 years ago
4 0

Answer:

When the leading coefficient is positive, the graph opens up. It means the vertex is its minimum.

When the leading coefficient is negative, the its vertex is its maximum.

  • f(x) - vertex is minimum
  • g(x) - vertex is maximum
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3/4 = x/60 what is the value of x in this equation?
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Please help Multiply -4w(w+2)
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What is -3/8 divided by -6/7? Help quick please
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Namaste :)

HERE IS YOUR ANSWER:

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The functions f and g are defined as follows f(x)=5x+3/6x+7 and g(x)= square root sign x^2-4x
telo118 [61]
<span>f(x)=5x+3/6x+7

This means that f(6/x) = [</span>5(6/x)+3] / [6(6/x)+7] = [ 30/x +3 ] / [36/x +7]

If we assume x≠0 ,    f(6/x) = [30 +3x]/ [36 + 7x]

g(x)=√<span> [ x^2-4x ]
</span>
g(x-4) = √ [ (x-4)^2-4(x-4) ] = √ [ x² -8x +16 -4x +16 ] = √ [ x^2-12x +32]
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3 years ago
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