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Lemur [1.5K]
3 years ago
5

A mother had a girl named Mia when she was 18. Four years later, when she was twenty two, she had triplets. Then a year later, a

t 23, she had another child. How old is the mother when the triplets are 12, the single child is 11 and the original child Mia is 16?
Mathematics
2 answers:
dexar [7]3 years ago
3 0
She was 22 when she had triplets
so if the triplets are 12 then just add 
22+12=34
or when she had Mia she was 18
if Mia is 16 then add
18+16=34
Also, she had another child at 23
if the child is 11 then add
23+11=34
Hope it helps! :)
Mnenie [13.5K]3 years ago
3 0
I believe the mom would be 34 years old!
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Tpy6a [65]
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3 years ago
2(x+y) = 61-2y<br> 4x-4 = 18-3y
Naddik [55]

Answer:

x = 8

y = -7

Step-by-step explanation:

This is a system of equations called simultaneous equations. We shall solve it by elimination method Step 1We shall label the equations (1) and (2)−3y−4x=−11.....(1)3y−5x=−61......(2)Step 2Multiply each term in equation (1) by 1 to give equation (3)1(-3y-4x=-11).....(1)-3y-4x=-11....(3)Step 3Multiply each term in equation 2 by -1 to give equation (4)-1(3y−5x=−61)......(2)-3y+5x=61.....(4)Step 4-3y-4x=-11....(3)-3y+5x=61.....(4)Subtract each term in equation (3) from each term in equation (4)-3y-(-3y)+5x-(-4x)=61-(-11)-3y+3y+5x+4x=61+110+9x=729x=72Step 5Divide both sides of the equation by 9, the coefficient of the unknown variable x to find the value of x 9x/9 = 72/9x = 8Step 6Put in x = 8 into equation (2)3y−5x=−61......(2)3y-5(8)=-613y-40=-61Collect like terms by adding 40 to both sides of the equation 3y-40+40=-61+403y=-21Divide both sides by 3, the coefficient of y to find the value of y 3y/3=-21/3y=-7Therefore, the values of x and y that satisfy the equations are 8 and -7 respectively

4 0
3 years ago
A factory makes 394 motorcycles each week. If there are 52 weeks in a year, how many motorcycles will they make in a year
BigorU [14]
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5 0
3 years ago
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Scilla [17]
K=2, because the bottom of the parabola shifted to the x value 2 from 0.

hope that helps
8 0
3 years ago
In ΔBCD, the measure of ∠D=90°, the measure of ∠C=83°, and DB = 95 feet. Find the length of BC to the nearest tenth of a foot.
Paha777 [63]

Answer:

95.7

Step-by-step explanation:

\sin C = \frac{\text{opposite}}{\text{hypotenuse}}=\frac{95}{x}

sinC=

hypotenuse

opposite

​

=

x

95

​

\sin 83=\frac{95}{x}

sin83=

x

95

​

x\sin 83=95

xsin83=95

Cross multiply.

\frac{x\sin 83}{\sin 83}=\frac{95}{\sin 83}

sin83

xsin83

​

=

sin83

95

​

Divide each side by sin 83.

x=\frac{95}{\sin 83}=95.7134\approx 95.7\text{ feet}

x=

sin83

95

​

=95.7134≈95.7 feet

Type into calculator and roundto the nearest tenth of a foot.

8 0
3 years ago
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