In ΔBCD, the measure of ∠D=90°, the measure of ∠C=83°, and DB = 95 feet. Find the length of BC to the nearest tenth of a foot.

Mathematics

1 answer:

Paha777 [63]3 years ago

8 0

Answer:

95.7

Step-by-step explanation:

\sin C = \frac{\text{opposite}}{\text{hypotenuse}}=\frac{95}{x}

sinC=

hypotenuse

opposite

\sin 83=\frac{95}{x}

sin83=

x\sin 83=95

xsin83=95

Cross multiply.

\frac{x\sin 83}{\sin 83}=\frac{95}{\sin 83}

sin83

xsin83

sin83

Divide each side by sin 83.

x=\frac{95}{\sin 83}=95.7134\approx 95.7\text{ feet}

sin83

=95.7134≈95.7 feet

Type into calculator and roundto the nearest tenth of a foot.

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sleet_krkn [62]

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Step-by-step explanation:

a) The tennis ball experiments a free fall, that is, an uniform accelerated motion due to gravity and in which effects from Earth's rotation and air viscocity are negligible. The height of the ball in time is represented by a second order polynomial. Hence, the vertex of the parabola is the initial point highlighted in graph.

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