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3 years ago

In ΔBCD, the measure of ∠D=90°, the measure of ∠C=83°, and DB = 95 feet. Find the length of BC to the nearest tenth of a foot.

Mathematics

1 answer:

Paha777 [63]3 years ago

8 0

Answer:

95.7

Step-by-step explanation:

\sin C = \frac{\text{opposite}}{\text{hypotenuse}}=\frac{95}{x}

sinC=

hypotenuse

opposite

\sin 83=\frac{95}{x}

sin83=

x\sin 83=95

xsin83=95

Cross multiply.

\frac{x\sin 83}{\sin 83}=\frac{95}{\sin 83}

sin83

xsin83

sin83

Divide each side by sin 83.

x=\frac{95}{\sin 83}=95.7134\approx 95.7\text{ feet}

sin83

=95.7134≈95.7 feet

Type into calculator and roundto the nearest tenth of a foot.

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