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3 years ago

7

Can someone help me for this question...please

1 answer:

lina2011 [118]3 years ago

3 0

Answer:

No value of x

Step-by-step explanation:

SEE the image for solution.

HOPE it helps

Have a great day

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If a certain number is increased by 5, one-half of the result is three fifths of the excess of 61 over the number. find the numb

Serggg [28]

Step-by-step explanation:

<h3>Let the number be x </h3><h3>X×5 =1/2 × 3/5 × 61</h3><h3>5X = 18 </h3><h3>X = 18/5 </h3><h3>X =3.3</h3>

4 0

3 years ago

svet-max [94.6K]

D.) <span>A picnic table is on sale for 40 percent off. The original price of the picnic table is x, $144.10

It is on sale for 40% so, new amount will be 60%, and x is the sale price, so in order to calculate original price, you have to multiply them

Hope this helps!</span>

8 0

4 years ago

What is the answer ?

Rainbow [258]

Answer:

C

Step-by-step explanation:

6 0

3 years ago

Determine what shape is formed for the given coordinates for ABCD, and then find the perimeter and area as an exact value and ro

Helga [31]

Answer:

Part 1) The shape is a trapezoid

Part 2) The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

Part 3) The area is $937.5\ units^2$

Step-by-step explanation:

step 1

Plot the figure to better understand the problem

we have

A(-28,2),B(-21,-22),C(27,-8),D(-4,9)

using a graphing tool

The shape is a trapezoid

see the attached figure

step 2

Find the perimeter

we know that

The perimeter of the trapezoid is equal to

$P=AB+BC+CD+AD$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

we have

A(-28,2),B(-21,-22)

substitute in the formula

$d=\sqrt{(-22-2)^{2}+(-21+28)^{2}}$

$d=\sqrt{(-24)^{2}+(7)^{2}}$

$d=\sqrt{625}$

$d_A_B=25\ units$

Find the distance BC

we have

B(-21,-22),C(27,-8)

substitute in the formula

$d=\sqrt{(-8+22)^{2}+(27+21)^{2}}$

$d=\sqrt{(14)^{2}+(48)^{2}}$

$d=\sqrt{2,500}$

$d_B_C=50\ units$

Find the distance CD

we have

C(27,-8),D(-4,9)

substitute in the formula

$d=\sqrt{(9+8)^{2}+(-4-27)^{2}}$

$d=\sqrt{(17)^{2}+(-31)^{2}}$

$d=\sqrt{1,250}$

$d_C_D=25\sqrt{2}\ units$

Find the distance AD

we have

A(-28,2),D(-4,9)

substitute in the formula

$d=\sqrt{(9-2)^{2}+(-4+28)^{2}}$

$d=\sqrt{(7)^{2}+(24)^{2}}$

$d=\sqrt{625}$

$d_A_D=25\ units$

Find the perimeter

$P=25+50+25\sqrt{2}+25$

$P=(100+25\sqrt{2})\ units$

simplify

$P=25(4+\sqrt{2})\ units$ ----> exact value

$P=135.4\ units$

therefore

The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

step 3

Find the area

The area of trapezoid is equal to

$A=\frac{1}{2}[BC+AD]AB$

substitute the given values

$A=\frac{1}{2}[50+25]25=937.5\ units^2$

4 0

3 years ago

Si el área de una figura rectangular esta dada por A-bxh,¿cual es la siguiente expresiones representa el área de la puerta

stealth61 [152]

Respuesta:

3x² + 5x - 2

Explicación paso a paso:

Dado que :

Área del rectángulo, A = largo * ancho

Dimensión = 3x - 1; x + 2

Área = (3x - 1) * (x + 2)

Área = 3x² + 6x - x - 2

Área = 3x² + 5x - 2

8 0

3 years ago