Answer:
Statements Reasons
1. 2x + 11 = 15 1. Given
2. 2x = 4 2. Subtraction Property of Equality
3. X = 2 3. Division Property of Equality
Step-by-step explanation:
An equation can be solved and its solution proven using algebraic theorems and properties. To create a proof, form two columns. Label one side Statements and the other Reasons.
Begin your proof listing the any information given to you. List as the reason - Given.
Then list the next step which here would be to subtract by 11 on both side. The reason is Subtraction Property of Equality. Subtraction is the inverse of addition. Inverse axiom is another acceptable reason.
Then divide both sides by 2. The reason is Division Property of Equality or Inverse axiom once again. See the proof below.
Statements Reasons
1. 2x + 11 = 15 1. Given
2. 2x = 4 2. Subtraction Property of Equality
3. X = 2 3. Division Property of Equality
<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>⤴</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em>
HI THIS IS VERY HARD CAN U GIVE ME MORE TIME
If x = # of quarters, then, the # of dimes will be equal to 2x. The total value (z) would be equal to:
z = 0.25x + 0.10(2x)
Then, since you switch the quarters and the dimes, and you have a new total, the resulting equation will be:
1.2 + z = 0.25(2x) + 0.10(x)
Plug in the values you know:
1.2 + (0.25x + 0.10(2x)) = 0.25(2x) + 0.10(x)
Solve for x:
1.2 + (0.25x + 0.20x) = 0.50x + 0.10x
1.2 + 0.45x = 0.60x
1.2 = 0.15x
x = 1.2/0.15 = 8
This means that there are 8 Quarters in her bag right now. So, the amount of dimes is just 2x which is 16. So your answer will be:
She has 8 Quarters and 16 Dimes in her bag right now. Or, $3.60.
If this doesn't make sense, then tell me. I have some resources where I got the answer from to put it into simplest terms. I have the website if you want.
Answer:
B
Step-by-step explanation:
We are 90% confident the proportion of students planning to attend public colleges who attended public high schools is between 0.0152 lower than to 0.2152 higher than the proportion of students planning to attend public colleges who attended private high schools.
