Answer:
x=7, y= 8
Step-by-step explanation:
x+y=15
x+2y=23
Subtract the first equation from the second equation to eliminate x
x+2y=23
-x-y=-15
--------------------
y = 8
Now we can find x
x+y = 15
x+8 = 15
Subtract 8 from each side
x+8-8=15-8
x = 7
Answer:
amplitude A = 5
vertical shift = 0
period T = 10 s
frequency = 1/T = 0.1 Hz
angular frequency ω = π/5
h(t) = 5sin(πt/5)
Step-by-step explanation:
An oscillator cannot move between ± 5 units, be at rest at t=0 and at maximum 2.5 s later without some serious external acceleration being applied. It just does not work.
I will ASSUME that the particle is at maximum velocity at t = 0 and use the remaining inputs as stated
As h(0) = 0 the Sine function fits nicely as sin0 = 0
A = 5 as the particle swings between +5 and -5
h(t) = 5sin(ωt)
ω will have units of rad/s
We know the particle will move from max to min position in half the period.
so the period T = 2(7.5 - 2.5) = 10 s
There are 2π radians in each cycle, therefore
ω = 2π rad/10 s = π/5 rad/s
h(t) = 5sin(πt/5)
The answer is A. here why. if we take the 45 times 5 you get the answer of how much she made all together for babysitting, if she only made 225 all together, you take 300-225=75. so the 75 represent the other she made by doing chores. you take 75 divide by 5 which is how many weeks it took it took you get 15 which how much she made each week by doing chores
Answer:
x²(x - 1)²
Step-by-step explanation
Given the expression x^4 - 2x^3 + x^2
Factoring out the common terms;
x^2 (x^2-2x + 1)
Factorize the expression in bracket
= x^2 (x^2-2x + 1)
= x^2 (x^2-x-x + 1)
= x^2 (x(x-1)-1(x-1))
= x^2 (x-1)(x-1)
<em>= x^2(x-1)^2</em>
<em>Hence the factored form of the expression is x²(x - 1)²</em>
