Answer:
Yes, △ABC ∼ △FED by AA postulate.
Step-by-step explanation:
Given:
Two triangles ABC and FED.
m∠A = m∠B
m∠C = m∠A + 30°
m∠E = m∠F = 
m∠D = 
°.
Now, let m∠A = m∠B = 
So, m∠C = m∠A + 30° = 
Now, sum of all interior angles of a triangle is 180°. Therefore,
m∠A + m∠B + m∠C = 180
Therefore, m∠A = 50°, m∠B = 50° and m∠C = m∠A + 30° = 50 + 30 = 80°.
Now, consider triangle FED,
m∠D+ m∠E + m∠F = 180
Therefore, m∠F = 50°
m∠E = 50° and
m∠D = 
So, both the triangles have congruent corresponding angle measures.
m∠A = m∠F = 50°
m∠B = m∠E = 50°
m∠C = m∠D = 80°
Therefore, the two triangles are similar by AA postulate.
First we can find the line RT which is the square root of 40^2-32^2 which is equal to 24.
RT=24
Right Triangle Altitude Theorem Part: The measure of the altitude drawn from the vertex of the right angle of a right triangle to its hypotenuse is the geometric mean between the measures of the two segments of the hypotenuse.
The geometric mean of 32 and TS is 24, so set up equation.
2nd root or square root of 32*TS=24
32*TS=576
TS=18
QS=18+32=50
I hope this answer helped if you have any questions feel free to ask me in the comments.
Answer: 252 in
Step-by-step explanation:
Answer: B. z-311+311=151+311
Step-by-step explanation:
You do the opposite since you want to get rid of 311
The slant height of a square pyramid with those specifications would be 6.7 units.
