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Anarel [89]
3 years ago
13

A cone ___ has a square base never always sometimes

Mathematics
2 answers:
nadya68 [22]3 years ago
8 0

Answer:

Never

Step-by-step explanation:

Cuz cone has a round base

pshichka [43]3 years ago
3 0

Answer:

never - a cone has a circular base

Step-by-step explanation:

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CD if c = 6 & d = 11
deff fn [24]

Answer:

66

Step-by-step explanation:

CD means to multiply C&D which means that you are multiplying 6*11

`11*6=66

5 0
1 year ago
Evaluate the expression without using a calculator.
Keith_Richards [23]

Answer:

D

Step-by-step explanation:

Since 16 is to the power of a negative fraction, we know it is going to be positive and less than one . Therefore the only answer available would be  1/2 or option D

7 0
3 years ago
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I NEED HELP!!!!
Allushta [10]

Answer:

B

Step-by-step explanation:

Cand D: A= bh

A: A = (a+b)/2h

E: A= 6a^2

3 0
3 years ago
PLEASE HELP ME T-T <br> I NEED IT’S SOLUTION
Vlada [557]

The area is 8_/3

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6 0
3 years ago
Questions attached as screenshot below:Please help me I need good explanations before final testI pay attention
Nikitich [7]

The acceleration of the particle is given by the formula mentioned below:

a=\frac{d^2s}{dt^2}

Differentiate the position vector with respect to t.

\begin{gathered} \frac{ds(t)}{dt}=\frac{d}{dt}\sqrt[]{\mleft(t^3+1\mright)} \\ =-\frac{1}{2}(t^3+1)^{-\frac{1}{2}}\times3t^2 \\ =\frac{3}{2}\frac{t^2}{\sqrt{(t^3+1)}} \end{gathered}

Differentiate both sides of the obtained equation with respect to t.

\begin{gathered} \frac{d^2s(t)}{dx^2}=\frac{3}{2}(\frac{2t}{\sqrt[]{(t^3+1)}}+t^2(-\frac{3}{2})\times\frac{1}{(t^3+1)^{\frac{3}{2}}}) \\ =\frac{3t}{\sqrt[]{(t^3+1)}}-\frac{9}{4}\frac{t^2}{(t^3+1)^{\frac{3}{2}}} \end{gathered}

Substitute t=2 in the above equation to obtain the acceleration of the particle at 2 seconds.

\begin{gathered} a(t=1)=\frac{3}{\sqrt[]{2}}-\frac{9}{4\times2^{\frac{3}{2}}} \\ =1.32ft/sec^2 \end{gathered}

The initial position is obtained at t=0. Substitute t=0 in the given position function.

\begin{gathered} s(0)=-23\times0+65 \\ =65 \end{gathered}

8 0
1 year ago
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