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irga5000 [103]
3 years ago
15

An IQ test is designed so that the mean is 100 and the standard deviation is 1010 for the population of normal adults. Find the

sample size necessary to estimate the mean IQ score of statistics students such that it can be said with 9595​% confidence that the sample mean is within 22 IQ points of the true mean. Assume that sigmaσequals=1010 and determine the required sample size using technology. Then determine if this is a reasonable sample size for a real world calculation.
Mathematics
1 answer:
Serjik [45]3 years ago
8 0

Answer:

n=(\frac{1.960(10)}{2})^2 =96.04 \approx 97

So the answer for this case would be n=97 rounded up to the nearest integer . And this value is reaonable and possible in the reality.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma represent the population standard deviation

n represent the sample size  

Solution to the problem

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =2 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got z_{\alpha/2}=1.960, replacing into formula (b) we got:

n=(\frac{1.960(10)}{2})^2 =96.04 \approx 97

So the answer for this case would be n=97 rounded up to the nearest integer . And this value is reaonable and possible in the reality.

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The position function of a particle in rectilinear motion is given by s(t) = 2t3 – 21t2 + 60t + 3 for t ≥ 0 with t measured in s
Norma-Jean [14]

The positions when the particle reverses direction are:

s(t_1)=55ft\\\\s(t_2)=28ft

The acceleraton of the paticle when reverses direction is:

a(t_1)=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=18\frac{ft}{s^{2}}

Why?

To solve the problem, we need to remember that if we derivate the position function, we will get the velocity function, and if we derivate the velocity function, we will get the acceleration function. So, we will need to derivate two times.

Also, when the particle reverses its direction, the velocity is equal to 0.

We are given the following function:

s(t)=2t^{3}-21t^{2}+60t+3

So,

- Derivating to get the velocity function, we have:

v(t)=\frac{ds}{dt}=(2t^{3}-21t^{2}+60t+3)\\\\v(t)=3*2t^{2}-2*21t+60*1+0\\\\v(t)=6t^{2}-42t+60

Now, making the function equal to 0, to find the times when the particle reversed its direction, we have:

v(t)=6t^{2}-42t+60\\\\0=6t^{2}-42t+60\\\\0=t^{2}-7t+10\\(t-5)*(t-2)=0\\\\t_{1}=5s\\t_{2}=2s

We know that the particle reversed its direction two times.

- Derivating the velocity function to find the acceleration function, we have:

a(t)=\frac{dv}{dt}=6t^{2}-42t+60\\\\a(t)=12t-42

Now, substituting the times to calculate the accelerations, we have:

a(t_1)=a(2s)=12*2-42=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=12*5-42=18\frac{ft}{s^{2}}

Now, substitutitng the times to calculate the positions, we have:

s(t_1)=2*(2)^{3}-21*(2)^{2}+60*2+3=16-84+120+3=55ft\\\\s(t_2)=2*(5)^{3}-21*(5)^{2}+60*5+3=250-525+300+3=28ft

Have a nice day!

3 0
3 years ago
Answer 1-2 no links.​
aleksley [76]

Answer:

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Step-by-step explanation:

Labor unions arose in the nineteenth century as increasing numbers of Americans took jobs in factories, mines, and mills in the growing industrial economy.

The Knights of Labor, founded in 1869, was the first major labor organization in the United States. The Knights organized unskilled and skilled workers, campaigned for an eight hour workday, and aspired to form a cooperative society in which laborers owned the industries in which they worked.

The Knights’ membership collapsed following the 1886 Haymarket Square riot in Chicago. By 1886 the American Federation of Labor (AFL), an alliance of skilled workers’ trade unions, was growing.

8 0
2 years ago
Read 2 more answers
PLZ HELP ME I REALLY NEED IT
kenny6666 [7]

r = 2 inches

total h of the cylinder = 6+6+6 = 18 inches

SA = 2\pi {r}^{2}  + 2\pi \: rh

= 2\pi \: r(r + h)

= 2 \times 3.14 \times 2(2 + 18)

= 2 \times 3.14 \times 2 \times 20

= 251.2square \: inches

4 0
3 years ago
17. You bought four cans of chicken noodle soup at the grocery store. You paid a total of 3.10
Brrunno [24]

Answer:

0.775

Step-by-step explanation:

Divide 3.10 by the number of cans you have. The total number of cans you have is 4. So divide 3.10 by 4 and you will have the answer of 0.775.

4 0
3 years ago
Read 2 more answers
Help please need to be done now​
4vir4ik [10]
The radius of the new sphere is 9


The new SA should be 1017.36 in



New volume should be 3052.08in^3
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3 years ago
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