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3 years ago

PLEASE HELP ME T-T I NEED IT’S SOLUTION

Mathematics

1 answer:

Vlada [557]3 years ago

6 0

The area is 8_/3

hope it helps.

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How does probability apply to basketball?

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3 years ago

Elijah can spend up to $23 on groceries. She wants to buy 3 pounds of tomatoes, 4 pounds of oranges, and x pounds of lean ground

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3 years ago

Choose one of the factors of x^3 + 343.

Debora [2.8K]

First, note that $343=7^3.$ Then use the formula for the sum of perfect cubes:

$a^3+b^3=(a+b)(a^2-ab+b^2).$

Therefore,

$x^3 + 343=x^3+7^3=(x+7)(x^2-7x+49).$

The quadratic trinomial $x^2-7x+49$ couldn't be factored anymore, so the expression $x^3 + 343$ has two factors $x+7$ and $x^2-7x+49.$

Answer: correct choice is A.

3 0

3 years ago

Help pleaseeeeeeeeeeeeeeeeeeeeeee

bixtya [17]

Answer: $\bold{(1)\ \dfrac{19,683}{64}\qquad (2)\ 16}$

<u>Step-by-step explanation:</u>

(1) (12, 18, 27, ...)

The common ratio is:

$r=\dfrac{a_{n+1}}{a_n}\quad r =\dfrac{18}{12}=\boxed{\dfrac{3}{2}}\quad \rightarrow \quad r=\dfrac{27}{18}=\boxed{\dfrac{3}{2}}$

The equation is:

$a_n=a_o(r)^{n-1}\\\\Given:a_o=12,\ r=\dfrac{3}{2}\\\\\\Equation:\\a_n =12\bigg(\dfrac{3}{2}\bigg)^{n-1}\\\\\\\\9th\ term:\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{9-1}\\\\\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{8}\\\\\\.\quad =\large\boxed{\dfrac{19643}{64}}$

$(2)\qquad \bigg(\dfrac{1}{16},\dfrac{1}{8},\dfrac{1}{4},\dfrac{1}{2}\bigg)\\\\\\\text{The common ratio is}:\\\\r=\dfrac{a_{n+1}}{a_n}\quad r=\dfrac{\frac{1}{8}}{\frac{1}{16}}=\boxed{2}\quad \rightarrow \quad r=\dfrac{\frac{1}{4}}{\frac{1}{8}}=\boxed{2}$

The equation is:

$a_n=a_o(r)^{n-1}\\\\Given:a_o=\dfrac{1}{16},\ r=2\\\\\\Equation:\\a_n =\dfrac{1}{16}(2)^{n-1}\\\\\\\\9th\ term:\\a_9=\dfrac{1}{16}(2)^{9-1}\\\\\\a_9=\dfrac{1}{16}(2)^{8}\\\\\\.\quad =\large\boxed{16}$

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3 years ago

What is 150% as a fraction

Helen [10]

150% as fraction is 150/100 = 15/10 = 3/2 and thats the simplest form :)))
i hope this is helpful
have a nice day

6 0

3 years ago

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