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2 years ago

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rounding me to the nearest hundred makes me 900. The sum of my digits is 25. If you read forward or backward, i am still same. w

hat number am i?

2 answers:

Mashutka [201]2 years ago

7 0

the no must be 858 o 868 or 878 or 888 or 898

8+5+8=21

8+6+8=22

8+7+8=23

8+8+8=24

8+9+8=25

now 898 is the most likely case here

lets go deep into it

approximating 898 to nearest hundred gives 900

addition of each character of 898 gives 25

reading forward and backward both 898 remains same

therefore 898 is the number which satisfies the given conditions. therefore the answer is 898

Read more on Brainly.com - brainly.com/question/10699402#readmore

Novosadov [1.4K]2 years ago

3 0

the no must be 858 o 868 or 878 or 888 or 898

8+5+8=21

8+6+8=22

8+7+8=23

8+8+8=24

8+9+8=25

now 898 is the most likely case here

lets go deep into it

approximating 898 to nearest hundred gives 900

addition of each character of 898 gives 25

reading forward and backward both 898 remains same

therefore 898 is the number which satisfies the given conditions. therefore the answer is 898

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A submarine sandwich 1.5feet long is cut into 0.25 foot pieces. how many pieces will there be?

MA_775_DIABLO [31]

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2 years ago

Read 2 more answers

The angle θ 1 is located in Quadrant IV, and cos ⁡ ( θ 1 ) = 9/ 19 , theta, start subscript, 1, end subscript, right parenthesis

Firdavs [7]

Answer:

$sin\theta_1 = - \frac{2\sqrt{70}}{19}$

Step-by-step explanation:

We are given that $\theta_1$ is in <em>fourth</em> quadrant.

$cos\theta_1$ is always positive in 4th quadrant and

$sin\theta_1$ is always negative in 4th quadrant.

Also, we know the following identity about $sin\theta$ and $cos\theta$ :

$sin^2\theta + cos^2\theta = 1$

Using \theta_1 in place of \theta:

$sin^2\theta_1 + cos^2\theta_1 = 1$

We are given that $cos\theta_1 = \frac{9}{19}$

$\Rightarrow sin^2\theta_1 + \dfrac{9^2}{19^2} = 1\\\Rightarrow sin^2\theta_1 = 1 - \dfrac{81}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{361-81}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{280}{361}\\\Rightarrow sin\theta_1 = \sqrt{\dfrac{280}{361}}\\\Rightarrow sin\theta_1 = +\dfrac{2\sqrt{70}}{19}, -\dfrac{2\sqrt{70}}{19}$

$\theta_1$ is in <em>4th quadrant </em>so $sin\theta_1$ is negative.

So, value of $sin\theta_1 = - \frac{2\sqrt{70}}{19}$

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2 years ago

Suppose f(x)=x^3 find the graph of f(x+3)

hoa [83]

Replace x with x+3:

f(x+3) = (x+3)²

which is x² translated 3 units left

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3 years ago

The rectangle shown has a perimeter of 44cm and the given area. Its length is 4 more than its width. Write and solve a system of

nasty-shy [4]

Answer:

Hope it helps◉‿◉Have a nice day.

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2 years ago

Need help question 4

zysi [14]

You need to find what 3 is if 5 is $520,000
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Therefore 3 is 312,000
Hope this helps :3

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3 years ago