5^5-9(200/4)-(10*90)/5-4^4(5)+156-256
= 3125-9( 200/4)-(10*90)/5-(4^4)(5)+156-256
= 3125-(9)(50)- (10*90)/5-(4^4)(5)+156-256
= 3125-450- (10*90)/5-(4^4)(5)+156-256
= 2675-(10*90)/5-(4^4)(5)+156-256
= 2675 - 900/5 - (4^4)(5)+156-256
= 2675 - 180 - (4^4)(5)+156-256
= 2495 - (4^4)(5)+156-256
= 2495 - 1280 + 156 -256
= 1215 + 156 - 256
= 1371 - 256
= 1115
I hope that's help , please if you have question(s) just let me know !
Answer:
the second one +1.5 m/s
Step-by-step explanation:
to find the velocity you need to find the slope of the two points then just put it into the time (s) and position (m) terms which equals +1.5 m/s
Answer:
$4.25
Step-by-step explanation:
Easy price is 85 so
Divide 85 by 100
0.85
then multiply by 5
0.85*5=4.25
Brainliest please and you're welcome
Answer:
≈ -5.1857
≈ -5.4857
≈ 3.7262
Step-by-step explanation:
Rewrite the equation system as:
Now, write the system in its augmented matrix form:
![\left[\begin{array}{cccc}6&8&0&-75\\-3&6&6&5\\2&-9&0&39\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D6%268%260%26-75%5C%5C-3%266%266%265%5C%5C2%26-9%260%2639%5Cend%7Barray%7D%5Cright%5D)
applying row reduction process to its associated augmented matrix:
Swap R1 and R3, and then Swap R1 and R2:
![\left[\begin{array}{cccc}-3&6&6&5\\2&-9&0&39\\6&8&0&-75\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-3%266%266%265%5C%5C2%26-9%260%2639%5C%5C6%268%260%26-75%5Cend%7Barray%7D%5Cright%5D)
R3+2R1
![\left[\begin{array}{cccc}-3&6&6&5\\2&-9&0&39\\0&20&12&-65\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-3%266%266%265%5C%5C2%26-9%260%2639%5C%5C0%2620%2612%26-65%5Cend%7Barray%7D%5Cright%5D)
3R2+2R1
![\left[\begin{array}{cccc}-3&6&6&5\\0&-15&12&127\\0&20&12&-65\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-3%266%266%265%5C%5C0%26-15%2612%26127%5C%5C0%2620%2612%26-65%5Cend%7Barray%7D%5Cright%5D)
15R3+20R2
![\left[\begin{array}{cccc}-3&6&6&5\\0&-15&12&127\\0&0&420&1565\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-3%266%266%265%5C%5C0%26-15%2612%26127%5C%5C0%260%26420%261565%5Cend%7Barray%7D%5Cright%5D)
Now we have a simplified system:
From (3):
(4)
Replacing (4) in (2)
(5)
Finally replacing (5) and (4) in (1)
Answer:
20°
Step-by-step explanation:
C70° vertically opposite... the alternate then vertically opposite again then 90° - 70° = 20°
