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3 years ago

14

Identify the axis of symmetry of the given quadratic y= -3x^2 - 12

1 answer:

Sergeeva-Olga [200]3 years ago

6 0

Answer:

$\frac{d}{dy}(-3x^{2} -12) = -6x$

0 = -6x

0 = x

$-3(0)^{2} -12 = -12$

(0,-12)

Step-by-step explanation:

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F(x)=2(x+1)^2-2 What is the vertex

Bumek [7]

Answer:

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Step-by-step explanation:

Let's bring back to memory vertex formula for parabolas.

$y=a(x-h)^{2}+k$

Where (h,k) is the vertex.

In $f(x)=2(x+1)^{2}-2$

The vertex is (-1,-2)

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Answer:

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Step-by-step explanation:

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3 years ago

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Greetings! Hope this helps!

Answer

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Step-by-step explanation:

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Step-by-step explanation:

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