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3 years ago

I need help on 21 can you please show your work

Mathematics

1 answer:

Oksanka [162]3 years ago

5 0

Start with stating the numerators

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Solve the triangle using law of cosines

klemol [59]

Answer:

What triangle..........?

5 0

3 years ago

What is the phase of y= -3cos (3x-pi) +5

ratelena [41]

Answer:

$- \frac{\pi}{3}$

Step-by-step explanation:

Given

$y = -3\cos(3x - \pi) + 5$

Required

The phase

We have:

$y = -3\cos(3x - \pi) + 5$

Rewrite as:

$y = -3\cos(3(x - \frac{\pi}{3})) + 5$

A cosine function is represented as:

$y = A\cos(B(x + C)) + D$

Where:

$C \to$ Phase

By comparison:

$C = - \frac{\pi}{3}$

Hence, the phase is: $- \frac{\pi}{3}$

3 0

3 years ago

For questions 3 – 5, an airplane is heading south at an airspeed of 540 km/hr, but there is a wind blowing from the northeast at

GuDViN [60]

First, let's calculate the horizontal and vertical components of the wind speed (W) and the airplane speed (A), knowing that south is a bearing of 270° and northeast is a bearing of 45°:

$\begin{gathered} W_x=W\cos45°\\ \\ W_x=50\cdot0.707\\ \\ W_x=35.35\\ \\ \\ \\ W_y=W\sin45°\\ \\ W_y=50\cdot0.707\\ \\ W_y=35.35 \end{gathered}$ $\begin{gathered} A_x=A\cos270°\\ \\ A_x=540\cdot0\\ \\ A_x=0\\ \\ \\ \\ A_y=A\sin270°\\ \\ A_y=540\cdot(-1)\\ \\ A_y=-540 \end{gathered}$

Now, let's add the components of the same direction:

$\begin{gathered} V_x=W_x+A_x=35.35+0=35.35\\ \\ V_y=W_y+A_y=35.35-540=-504.65 \end{gathered}$

To find the resultant bearing (theta), we can use the formula below:

$\begin{gathered} \theta=\tan^{-1}(\frac{V_y}{V_x})\\ \\ \theta=\tan^{-1}(\frac{-504.65}{35.35})\\ \\ \theta=-86° \end{gathered}$

The angle -86° is equivalent to -86 + 360 = 274°.

Therefore the correct option is b.

8 0

1 year ago

Solve -14-5y >-64<br> A. Y<10<br> B.y>-10<br> C. Y>10<br> D.y<-10

amm1812

Hello :D

Answer:

A. $Y$

Step-by-step explanation:

First, you add by 14 both sides of an equation.

-14-5y+14>-64+14

Then, simplify by equation.

-64+14=-50

-5y>-50

Multiply -1 both sides.

(-5y)(-1)<(-50)(-1)

5y<50

Divide by 5 both sides of an equation.

5y/5<50/5

Divide numbers from left to right.

50/5=10

y<10 is the correct answer.

Hope this helps you! :D

6 0

3 years ago

How do you write 2.6 × 10 to the 3 power in standard form?

Novay_Z [31]

Answer:

no u

Step-by-step explanation:

7 0

3 years ago