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icang [17]
4 years ago
12

Bethany sells roses and petunias. The expression 3r+2.5p3r+2.5p gives the cost (in dollars) of rr roses and pp petunias. What is

the cost of 77 roses and 88 petunias? \$
Mathematics
2 answers:
yawa3891 [41]4 years ago
5 0

Answer:

The cost of 7 roses and 8 petunias is $9001

Step-by-step explanation:

We are given expression for cost as

C=3r+2.5p^3r+2.5p

where

r is number of roses

p is petunias

We are given

r=7

and

p=8

so, we can plug here

C=3(7)+2.5(8)^3(7)+2.5(8)

now, we can simplify it

and we get

C=9001

So,

The cost of 7 roses and 8 petunias is $9001

Minchanka [31]4 years ago
4 0

Answer:

$41.

Step-by-step explanation:

We have been given an expression 3r+2.5p, which gives the cost in dollars of r roses and p petunias.

To find the cost of 7 roses and 8 petunias we will substitute r=7 and p=8 in our given expression.

\text{Cost of 7 roses and 8 petunias}=3\times 7+2.5\times 8

\text{Cost of 7 roses and 8 petunias}=21+20

\text{Cost of 7 roses and 8 petunias}=41

Therefore, the cost of 7 roses and 8 petunias is $41.

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