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3 years ago

What Event is called when an Object collides with an non-trigger collider?

Computers and Technology

1 answer:

IrinaVladis [17]3 years ago

7 0

option 3 is right

on collisionenter

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A ____ by a design professional is used to determine the best system to provide the appropriate level and type of protection.

AleksAgata [21]

A HAZARD EVALUATION by a design professional is used to determine the best system to provide the appropriate level and type of protection. Hazard evaluation involves systematic identification and analysis of hazards that are associated with a particular product or process. This gives one the opportunity to avoid these hazards.

8 0

3 years ago

the volume of two similar solids are 1080cm and 1715cm .if the curved surface area of the smaller cone is 840cm .fond the curved

gavmur [86]

Answer:

$A_{big} = 1143.33cm^2$

Explanation:

The given parameters are:

$V_{small} = 1080$

$V_{big} = 1715$

$C_{small} = 840$

Required

Determine the curved surface area of the big cone

The volume of a cone is:

$V = \frac{1}{3}\pi r^2h$

For the big cone:

$V_{big} = \frac{1}{3}\pi R^2H$

Where

R = radius of the big cone and H = height of the big cone

For the small cone:

$V_{small} = \frac{1}{3}\pi r^2h$

Where

r = radius of the small cone and H = height of the small cone

Because both cones are similar, then:

$\frac{H}{h} = \frac{R}{r}$

and

$\frac{V_{big}}{V_{small}} = \frac{\frac{1}{3}\pi R^2H}{\frac{1}{3}\pi r^2h}$

$\frac{V_{big}}{V_{small}} = \frac{R^2H}{r^2h}$

Substitute values for Vbig and Vsmall

$\frac{1715}{1080} = \frac{R^2H}{r^2h}$

Recall that: $\frac{H}{h} = \frac{R}{r}$

So, we have:

$\frac{1715}{1080} = \frac{R^2*R}{r^2*r}$

$\frac{1715}{1080} = \frac{R^3}{r^3}$

Take cube roots of both sides

$\sqrt[3]{\frac{1715}{1080}} = \frac{R}{r}$

Factorize

$\sqrt[3]{\frac{343*5}{216*5}} = \frac{R}{r}$

$\sqrt[3]{\frac{343}{216}} = \frac{R}{r}$

$\frac{7}{6} = \frac{R}{r}$

The curved surface area is calculated as:

$Area = \pi rl$

Where

$l = slant\ height$

For the big cone:

$A_{big} = \pi RL$

For the small cone

$A_{small} = \pi rl$

Because both cones are similar, then:

$\frac{L}{l} = \frac{R}{r}$

and

$\frac{A_{big}}{A_{small}} = \frac{\pi RL}{\pi rl}$

$\frac{A_{big}}{A_{small}} = \frac{RL}{rl}$

This gives:

$\frac{A_{big}}{A_{small}} = \frac{R}{r} * \frac{L}{l}$

Recall that:

$\frac{L}{l} = \frac{R}{r}$

So, we have:

$\frac{A_{big}}{A_{small}} = \frac{R}{r} * \frac{R}{r}$

$\frac{A_{big}}{A_{small}} = (\frac{R}{r})^2$

Make $A_{big}$ the subject

$A_{big} = (\frac{R}{r})^2 * A_{small}$

Substitute values for $\frac{R}{r}$ and $A_{small}$

$A_{big} = (\frac{7}{6})^2 * 840$

$A_{big} = \frac{49}{36} * 840$

$A_{big} = \frac{49* 840}{36}$

$A_{big} = 1143.33cm^2$

<em>Hence, the curved surface area of the big cone is 1143.33cm^2</em>

4 0

3 years ago

Give me give me keyboard on this phone please provide nice I can't type where is the keyboard.Give me give me keyboard on this p

RSB [31]

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3 years ago

Read 2 more answers

In object-oriented analysis, an object is a member of a(n) _____, which is a collection of similar objects.

Advocard [28]

In object-oriented analysis, an object is a member of a CLASS, which is a collection of similar objects. It is a software engineering method.

<h3>Object-oriented analysis </h3>

Object-oriented analysis and design can be defined as a software engineering methodology.

This methodology (object-oriented analysis) is used to model a system as a particular group of interacting objects.

The object-oriented analysis is characterized due to the fact that objects are organized according to particular classes.

Learn more about object-oriented analysis here:

brainly.com/question/3522354

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2 years ago

Ideation includes all of the following EXCEPT

chubhunter [2.5K]

i believe it would be either C or D im sorry i dont know the exact answer

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3 years ago