Answer:
#include <iostream>
#include <stack>
#include <queue>
#include <string>
int main()
{
while ( true )
{
std::string letters;
std::cout << "Please enter a word (Enter - exit): ";
std::getline( std::cin, letters );
if ( letters.empty() ) break;
std::stack<char>
s( std::stack<char>::container_type( letters.begin(), letters.end() ) );
std::queue<char>
q( std::queue<char>::container_type( letters.begin(), letters.end() ) );
while ( !s.empty() && s.top() == q.front() )
{
s.pop();
q.pop();
}
if ( s.empty() ) std::cout << "The word is a palindrome" << std::endl;
else std::cout << "The word is not a palindrome" << std::endl;
}
return 0;
}
Explanation:
A <em>stack</em> is used to replicate a stack data structure in C++ while <em>Queue </em>container is a replica of the queue data structure in C++, Unlike stack, in the queue container, there are two ends, i.e. front, and back.
In the code above to be able to use used stack and queue, we included the headers #include <stack> and#include <queue>.
Answer:
yes oo you want to play with me
I have a very good example of the program you need written on Python. You can use this (sorry for bad tabulation):
import math
import math
def main():
function = input("Enter a function f(x):\n")
x = 0
y = 0
for rows in range(10,-11,-1):
for col in range(-10,11,1):
x=col
roundfx = round(eval(function))
if roundfx == rows:
print("o", end="")
if rows==0 and col==0 and not rows == roundfx:
print("+", end="")
if col == 0 and not rows == 0 and not rows == roundfx:
print("|", end="")
if rows==0 and not col==0 and not rows == roundfx:
print("-", end="")
else:
if not rows == 0:
if not col == 0:
if not rows == roundfx:
print(" ", end="")
print()
main()
The security specialist has discovers a malicious script on a computer known as a logic bomb.
<h3>Is logic bomb a type of malware?</h3>
A logic bomb is known to be a form of a malicious program that is set up or ignited if a logical condition is met, such as after a series of transactions have been done, or on a given date.
Therefore, The security specialist has discovers a malicious script on a computer known as a logic bomb.
Learn more about malware from
brainly.com/question/399317
#SPJ1
Answer:
function countWords(sentence) {
return sentence.match(/\S+/g).length;
}
const sentence = 'This sentence has five words ';
console.log(`"${sentence}" has ${countWords(sentence)} words` );
Explanation:
Regular expressions are a powerful way to tackle this. One obvious cornercase is that multiple spaces could occur. The regex doesn't care.
