The answer is an usb port
In the C programming language, you can't determine the array size from the parameter, so you have to pass it in as an extra parameter. The solution could be:
#include <stdio.h>
void swaparrayends(int arr[], int nrElements)
{
int temp = arr[0];
arr[0] = arr[nrElements - 1];
arr[nrElements - 1] = temp;
}
void main()
{
int i;
int myArray[] = { 1,2,3,4,5 };
int nrElements = sizeof(myArray) / sizeof(myArray[0]);
swaparrayends(myArray, nrElements);
for (i = 0; i < nrElements; i++)
{
printf("%d ", myArray[i]);
}
getchar();
}
In higher languages like C# it becomes much simpler:
static void Main(string[] args)
{
int[] myArray = {1, 2, 3, 4, 5};
swaparrayends(myArray);
foreach (var el in myArray)
{
Console.Write(el + " ");
}
Console.ReadLine();
}
static void swaparrayends(int[] arr)
{
int temp = arr[0];
arr[0] = arr.Last();
arr[arr.Length - 1] = temp;
}
Answer:
oh no thanks not good
Explanation:
did you try it on a different device mabye a phone
A program that is required to three (3) numbers. calculate and print their total is given below:
<h3>The Program</h3>
import java.util.Scanner;
public class SumAndAverage {
public static void main(String[ ] args) {
System.out.println("Enter three numbers - ");
// Accepting and finding sum of numbers.
int sum = 0;
Scanner sc = new Scanner(System.in);
for (int i = 0; i < 3; i++)
sum += sc.nextInt( );
// Printing sum and average.
System.out.println("Sum - " + sum);
System.out.println("Average - " + (sum / 3f));
}
}
The output would request three different numbers, then add them up, and display the output of the sum and then display or print their total
Read more about programming here:
brainly.com/question/23275071
#SPJ1
