Answer:
Either leave it blank or type zero
Explanation:
Answer:
D - 14
Explanation:
Each time the program executes an iteration of the for-loop, it works out the current element by adding 3 to the previous element.
alpha[0] = 2
+3
alpha[1] = 5
+3
alpha[2] = 8
+3
alpha[3] = 11
+3
alpha[4] = 14
Answer:
The explanation for the question is given in the Explanation section below.
Explanation:
Throughout the query, we gave that we already have 8 core 3 GHz CMP and therefore it performs workflow in 2.0 CPI.
So,
(8 cores*3 GHz) /2.0 CPI = 12 billion/second guidance, we've turned GHz into seconds, so that's a billion years.
Well into the question considering whether he loses 6.67 L2 per 1 K direction.
So,
12*0.00667 = 80 million mistakes per second level-2. For an 8, so 32B*80 = 2560 MB per sec.
Whether the maximum storage capacity is double that of high as 2560*2 = 5120 MB per sec.
However, that's just throughout the DDR2-67 DIMM range. So, we should infer this, because only one storage source could be enough.
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I believe your question is incomplete. Please rewrite it again completely. Thanks